6KOH + \(Al_2\left(SO_4\right)_3\rightarrow3K_2SO_4+2Al\left(OH\right)_3\)
\(6KOH+Al_2\left(SO_4\right)_3\rightarrow3K_2SO_4+2Al\left(OH\right)_3\)
Al2(SO4)3 + 6KOH -> 2Al(OH)3 + 3K2SO4
nếu KOH dư: KOH+Al(OH)3->KAlO2+2H2O
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6KOH + Al2(SO4)3 \(\rightarrow\) 3K2SO4 + 2Al(OH)3
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