Khí thoát ra là etilen
\(n_{Ag2C2}=\frac{24}{240}=0,1\left(mol\right)=n_{C2H2}\left(BTC\right)\)
\(\Rightarrow V_{C2H2}=0,1.22,4=2,24\left(l\right)\)
\(\Rightarrow V=V_{C2H4}=3,36-22,4=1,12\left(l\right)\)
\(\Rightarrow\left\{{}\begin{matrix}\%V_{C2H2}=\frac{2,24}{3,36}.100\%=66,67\%\\\%V_{C2H4}=100\%-66,67\%=33,33\%\end{matrix}\right.\)