CaCO3 => (to) CaO + CO2
CaCO3 + C => (to) CaO + 2CO
P2O5 + 3H2O => H3PO4
*** Fe + 2HCl => FeCl2 + H2
mHCl = 200x18.25 / 100 = 36.5 (g)
nHCl = m/M = 1 (mol) => nFe = 0.5 (mol)
====> mFe = n.M = 0.5 x 56 = 28 (g)
Theo pt ==> nH2 = nFeCl2 = 0.5 (mol)
VH2 = 22.4 x 0.5 = 11.2 (l)
mdd sau pứ = 200 + 28 - 1 = 227 (g)
mFeCl2 = n.M = 127 x 0.5 = 63.5 (g)
C% = 63.5 x 100/227 = 27.97 %