theo đề bài:
a)nH2=2,24/22,4=0,1mol
PTPU
Zn+2HCl->ZnCl2+H2
0,1......0,2......0,1......0,1(mol)
ZnO+2HCl->ZnCl2+H2O
x.........2x..........x..........x(mol)
mZn+mZnO=mhh
65.0,1+81.x=14,6
=>x=0,1mol
%mZn\(\dfrac{65.0,1.100}{14,6}=44,52\%\)
%mZnO=100-44,52=55,48%
b)nZnCl2=0,1+0,1=0,2mol
mZnCl2=0,2.136=27,2g