a, \(\xi\)b = 4\(\xi\) = 4.4,5 = 18(V)
rb = 4 (\(\Omega\))
b, \(I_m=\dfrac{\xi_b}{R_N+r_b}=\dfrac{\xi_b}{R_1+R_2+r_b}=\dfrac{18}{3+5+4}=1,5\left(A\right)\)
\(\)\(P=I^2R=\left(1,5\right)^2.\left(3+5\right)=18\left(W\right)\)
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