Question

Giúp mình câu 6-7 với lại

Answer 1

áp dụng công thức :\(v=v_0+at\Rightarrow v_0=-2a\)

và\(v^2-v^{2_0}=2as\Rightarrow v^{2_0}=2as\Rightarrow\left(2a\right)^2=3.6a\)

\(\Rightarrow a=\dfrac{3.6}{4}m/s^2\)

ADCT:\(F_{hl}=ma\Rightarrow F=500\cdot\dfrac{3.6}{4}=450N\)

Answer 2

m₁=\(\dfrac{F}{a_1}\)

m₂=\(\dfrac{F}{a_2}\)

=> a=\(\dfrac{F}{\dfrac{F}{a_1}+\dfrac{F}{a_2}}=\dfrac{1}{\dfrac{1}{2}+\dfrac{1}{3}}\)=1.2m/s²