\(n_{CO_2}=\dfrac{3,84}{24}=0,16\left(mol\right)\Rightarrow n_C=0,16\left(mol\right)\\n_{H_2O}=\dfrac{3,6}{18}=0,2\left(mol\right)\Rightarrow n_H=0,4\left(mol\right)\\ n_{N_2}=\dfrac{0,96}{24}=0,04\left(mol\right)\Rightarrow n_N=0,08\left(mol\right)\\m_O=3,44-\left(0,16.12+0,4.1+0,08.14\right)=0\\ \Rightarrow AkhôngchứaO\\ VậyAđượctạobởicácnguyêntố:C,H,N \)