a/ \(C_2H_6\rightarrow C_2H_4+H_2\)
\(C_2H_4\left(\frac{50000}{33}\right)+Cl_2\rightarrow CH_2Cl-CH_2Cl\left(\frac{50000}{33}\right)\)
b/ \(m_{C_2H_4Cl_2}=500.300=150000\)
\(\Rightarrow n_{C_2H_4Cl_2}=\frac{150000}{99}=\frac{50000}{33}\)
\(\Rightarrow m_{C_2H_4\left(pứ\right)}=\frac{50000}{33}.28=\frac{1400000}{33}\)
\(\Rightarrow m_{C_2H_4\left(tt\right)}=\frac{1400000}{33.90\%}=47138,15\left(g\right)\)