\(CaO+2HCl\rightarrow CaCl_2+H_2O\left(1\right)\)
\(CaCO_3+2HCl\rightarrow CaCl_2+H_2O+CO_2\left(2\right)\)
Ta có:
\(n_{CO2}=\frac{8,96}{22,4}=0,04\left(mol\right)\)
Theo PTHH 2:
\(n_{CaCO3}=n_{CO2}=0,04\left(mol\right)\)
\(\Rightarrow m_{CaCO3}=0,04.100=4\left(g\right)\)
\(n_{CaCl2}=n_{CO2}=0,04\left(mol\right)\)
\(\Rightarrow m_{CaCl2\left(2\right)}=0,04.111=4,44\left(g\right)\)
\(\Rightarrow m_{CaCl2\left(2\right)}=6,66-4,44=2,22\left(g\right)\)
\(n_{CaCl2\left(1\right)}=\frac{2,22}{111}=0,02\left(mol\right)\)
Theo PTHH 1:
\(n_{CaO}=n_{CaCl2}=0,02\left(mol\right)\)
\(\Rightarrow m_{CaO}=0,02.56=1,12\left(g\right)\)
\(\Sigma m_{hh\left(CaO\right)+CaCO3}=m_{CaCO3}+m_{CaO}=1,12+4=5,12\left(g\right)\)
\(\%m_{CaO}=\frac{1,12}{5,12}.100\%=21,875\%\)
\(\%m_{CaCO3}=100\%-21,875\%=78,125\%\)
