a, \(2Al+6HCl\rightarrow2AlCl_3+3H_2\)
\(Zn+2HCl\rightarrow ZnCl_2+H_2\)
b, Ta có :
\(n_{H2}=\frac{4,48}{22,4}=0,2\left(mol\right)\)
\(\Rightarrow n_{HCl}=2n_{H2}=0,2.2=0,4\left(mol\right)\)
BTKL,
\(m_{hh}+m_{HCl}=m+m_{H2}+m_{Cu}\)
\(\Rightarrow m=9,15+0,4.36,5-0,2.2-3,2=20,15\left(g\right)\)