a)\(n_{Fe}:\dfrac{14}{56}=0,25\left(mol\right)\)
\(Fe+H_2SO_4\rightarrow FeSO_4+H_2\)
1................................1,,,,,,,,,,,,1(mol)
0,25...........................0,25......0,25(mol)
\(V_{H_2}:0,25.22,4=5,6\left(l\right)\)
b)
\(m_{FeSO_4}:0,25.152=38\left(g\right)\)
c)
\(CuO+H_2\underrightarrow{t^o}Cu+H_2O\)
1...............1........1..............(mol)
0,25.........0,25,,,,0,25..........(mol)
\(m_{Cu}:0,25.64=16\left(g\right)\)