a) Zn + 2HCl\(\rightarrow\)ZnCl2 + H2
b)
BTKL: mZn+mHCl=mZnCl+ mH2
\(\rightarrow\)mZnCl2=mZn + mHCl-mH2
=13+14,6-0,4=27,2 gam
c)
Tỉ lệ Zn:HCl:ZnCl2:H2=1:2:1:1
Zn : H:Cl=1:2:2
a) Zn + 2HCl→→ZnCl2 + H2
b)
BTKL: mZn+mHCl=mZnCl+ mH2
→→mZnCl2=mZn + mHCl-mH2
=13+14,6-0,4=27,2 gam
ti le 1:2:2