Phản ứng xảy ra:
\(Zn+2HCl\rightarrow ZnCl_2+H_2\)
Ta có:
\(n_{Zn}=\frac{13}{65}=0,2\left(mol\right)=n_{H2}\)
\(\Rightarrow V_{H2}=0,2.22,4=4,48\left(l\right)\)
\(n_{HCl}=2n_{Zn}=0,2.2=0,4\left(mol\right)\)
\(\Rightarrow m_{HCl}=0,4.36,5=14,6\left(g\right)\)
\(\Rightarrow m_{HCl\left(tg\right)}=14,6.120\%=17,52\left(g\right)\)