- Gọi \(\left\{{}\begin{matrix}n_{Fe}:a\left(mol\right)\\n_{Mg}:b\left(mol\right)\end{matrix}\right.\)
\(Fe+2HCl\rightarrow FeCl_2+H_2\)
a _____________a______a
\(Mg+2HCl\rightarrow MgCl_2+H_2\)
b________________b ___b
Giải hệ PT :
\(\left\{{}\begin{matrix}56a+24b=10,4\\a+b=\frac{6,72}{22,4}=0,3\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}a=0,1\\b=0,2\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}m_{Fe}=0,1.56=5,6\left(g\right)\\m_{Mg}=0,2.24=4,8\left(g\right)\end{matrix}\right.\)
\(m_{muoi}=m_{FeCl2}+m_{MgCl2}=0,1.127+0,2.95=31,7\left(g\right)\)