Gọi \(\left\{{}\begin{matrix}n_{etilen}:x\left(mol\right)\\n_{propilen}:y\left(mol\right)\end{matrix}\right.\)
\(C_2H_4+Br_2\rightarrow C_2H_4Br_2\)
\(C_3H_6+Br_2\rightarrow C_3H_6Br_2\)
Ta có:
\(n_{Br2}=\frac{25,6}{80.2}=0,16\left(mol\right)\)
Giải hệ PT:
\(\left\{{}\begin{matrix}28+42y=5,32\\x+y=0,16\end{matrix}\right.\)\(\Rightarrow\left\{{}\begin{matrix}x=0,1\\y=0,06\end{matrix}\right.\)
\(\Rightarrow m_{C2H4}=0,1.28=2,8\left(g\right)\)
\(\Rightarrow\left\{{}\begin{matrix}\%m_{C2H4}=\frac{2,8}{5,32}.100\%=52,63\%\\\%m_{C3H6}=100\%-52,63\%=47,37\%\end{matrix}\right.\)