Question

câu 2 này làm nhưthế nào ạ?

Answer 1

https://i.imgur.com/sUtqdkH.png

Answer 2

a)nNO=\(\frac{1,344}{22,4}\)=0,06(mol)

Gọi a là số mol Al b là số mol Cu

Ta có\(\left\{{}\begin{matrix}\text{27a+64b=4,38}\\\text{3a+2b=0,06.3=0,18}\end{matrix}\right.\rightarrow\left\{{}\begin{matrix}\text{a=0,02}\\\text{b=0,06}\end{matrix}\right.\)

mAl=0,02.27=0,54(g)

mCu=0,06.64=3,84(g)

b)

4Al(NO3)3\(\rightarrow\)2Al2O3+12NO2+3O2

2Cu(NO3)\(\rightarrow\)2CuO+4NO2+O2

nAl2O3=\(\frac{0,02}{2}\)=0,01(mol)

nCuO=0,06(mol)

m=0,01.102+0,06.0=5,82(g)