a) \(n_{CaCO_3}=0,25\left(mol\right)=n_{CO_2}\)
\(\Rightarrow\overline{C}=\frac{n_{CO_2}}{n_{hh}}=2,5\)
Do hh gồm 2 ankin liên tiếp
\(\Rightarrow\left\{{}\begin{matrix}A\text{ là }C_2H_2\left(axetilen\right)\\B\text{ }là\text{ }C_3H_4\left(propin\right)\end{matrix}\right.\)
b)
\(3C_2H_2\xrightarrow[C]{600^oC}C_6H_6\)
\(C_2H_2+H_2\xrightarrow[t^o]{PbCO_3/Pd}C_2H_4\\ C_2H_2+2AgNO_3+2NH_3\rightarrow C_2H_2Ag_2+2NH_4NO_3\\ CH\equiv CH+HCl\rightarrow CH_2=CHCl\\ nCH_2=CHCl\xrightarrow[t^o;P]{xt}\left(-CH_2-CHCl-\right)n\\ CH\equiv CH\text{ }\xrightarrow[t^o;P]{NH_4Cl;CuCl}\text{ }CH\equiv C-CH=CH_2\\ CH\equiv C-CH=CH_2+H_2\text{ }\xrightarrow[PbCO_3/Pd]{t^o}\text{ }CH_2=CH-CH=CH_2\\ CH_2=CH-CH=CH_2\xrightarrow[xt]{t^o;P}\left(-CH_2-CH=CH-CH_2-\right)_n\)
c) \(CH\equiv C-CH_2+H_2\xrightarrow[PbCO_3/Pd]{t^o}CH=CH-CH_2\)
\(CH\equiv C-CH_2+Br_2\rightarrow CHBr_2-CBr_2-CH_2\)
