Ta có: \(\left\{{}\begin{matrix}n_{CO_2}=0,1\left(mol\right)\\n_{NaOH}=0,015\left(mol\right)\end{matrix}\right.\)
\(\Rightarrow\dfrac{n_{NaOH}}{n_{CO_2}}=\dfrac{0,015}{0,1}=0,15\)
=> Tạo muối NaHCO3
\(CO_2\left(0,015\right)+NaOH\left(0,015\right)\rightarrow NaHCO_3\left(0,015\right)\)
\(\Rightarrow C_{M_{NaHCO_3}}=\dfrac{0,015}{0,015}=1\left(M\right)\)