Rút gọn phân số
a)\(\frac{-360}{450}\)
b)\(\frac{-260}{-1500}\)
c)\(\frac{2.3.5.13}{26.35}\)d)\(\frac{18.6-18}{\left(-36\right)\left(-5\right)}\)E)\(\frac{6.4+6.7}{6.5+12}\)F)\(\frac{25.9-25.17}{-8.80-8.10}\)g)\(\frac{^{3^2.5-3^6}}{3^4.13-3^4}\)
Rút gọn các phân số sau
a)\(\frac{2.3.5.13}{26.35}\)
b)\(\frac{18.6-18}{\left(-36\right).\left(-5\right)}\)
c)\(\frac{6.4+6.7}{6.5+12}\)
f)\(\frac{25.9-25.17}{-8.80-8.10}\)
g)\(\frac{3^4.5-3^6}{3^4.13-3^4}\)
a)2.3.5.13/26.35
=2.3.5.13/2.13.5.7
=3/7
b)18.6-18/-36.(-35)
=18.6-18/-(36.25)=18(6-1)/-(36.35)
=18.5/-(36.35)=2.3.3.5/-(2.2.3.3.5.7)
=-1/14
c)6.4+6.7/6.5+12=6.4+6.7/6.5+6.2
=6(4+7)/6(5+2)
=11/10
d)25.9-25.17/-8.80-8.10=25(9-17)/8(-80-10)
=25.(-8)/8(-90)
=5/18
e) 34.5-36/34.13-34
=34(5-32)/34(13-1)
=5-32/13-1=-1/3
bài 1 viết các phân số sau dưới dạng phân số có mẫu dương
\(\frac{-22}{-37}\);\(\frac{3}{-19}\);\(\frac{-11}{-39}\);\(\frac{-51}{-57}\)
bài 2 rút gọn các phân số sau
a. \(\frac{-360}{450}\) b. \(\frac{-260}{-1500}\) c. \(\frac{2.3.5.13}{26.35}\) d.\(\frac{18.6-18}{\left(-36\right).\left(-5\right)}\)
bài 3 tìm số nguyên x để các phân số sau là số nguyên
a. \(\frac{13}{x-1}\) b. \(\frac{x+3}{x-2}\)
CÁC BẠN GIÚP MÌNH VỚI!!!!!!!!!! HUHU
rút gọn và so sánh
\(\frac{25.9-25.17}{-8.80-8.10}va\frac{48.12-48.15}{-3.270-3.30}\)
25.9-25.17/-8.80-.10=25.(9-17)/-8(80+10)=25.(-8)/-8.90=25/90=5/18
48.12-48.15/-3.270-3.30=48.(12-15)/-3(270+30)=48.-3/-3.300=48/300=4/25
thông cảm e mới học lớp 6 nên sai thì thôi còn chỗ -3 hay -8 là vì thay -2 lần trừ ra cộng
\(\frac{-360}{450}\);\(\frac{2.3.5.13}{26.35}\)
rút gọn phân số
RÚT GỌN
a/ \(\frac{3939-101}{3.2929+505}\)
c/ \(\frac{6.9-2.17}{63.3-119}\)
d/ \(\frac{25.9-25.17}{-8.80-8.10}\)
e/ \(\frac{48.12-48.15}{-3.270-3.30}\)
ai nhanh nhất mình tíck
Rút gọn :
a, 3939-101/3.2929+505
b, 6.4+6.7/6.5+12
c,6.9+2.17/63.3-119
d, 25.9-25.17/-8.80-8.10
e, 48.12-48.15/-3.270-3.30
f, 25.7+25/25.52-25.3
g, 34.5-36/34.13+34
a/\(\frac{3939-101}{3.2929+505}=\frac{39.101-101}{8787+505}=\frac{101.\left(39-1\right)}{87.101+5.101}=\frac{101.38}{101.\left(87+5\right)}=\frac{38}{92}\)
\(=\frac{38}{92}\)
b/\(\frac{6.4+6.7}{6.5+12}=\frac{4+1.7}{1.5+2}=\frac{4+7}{5+2}=\frac{11}{7}\)
\(\frac{6.4+6.7}{6.5+12}\)\(=\frac{6.4+6.7}{6.5+6.2}\)\(=\frac{6.\left(4+7\right)}{6.\left(5+2\right)}\)\(=\frac{6.11}{6.7}\)\(=\frac{11}{7}\)
rút gọn rồi quy đồng các phân số sau đây:
a) \(\frac{7.12^3+2.12^3}{4^6.3^{11}};\frac{-17.10+17.6}{18.11+18.6};\frac{6.7.8.10}{9.12.14.15}\)
b) \(\frac{4.3^9+8.\left(-3\right)^7}{\left(-3\right)^{10}+20.\left(-3\right)^7};\frac{5^6.8-5^7}{5^8-7.5^6};\frac{-1997.1996+1}{-1995.\left(-1997\right)+1996}\)
Rút gọn phân số
a.\(\frac{25.9-25.17}{-8.80-8.10}\)
b.\(\frac{48.12-48.15}{-3.270-3.30}\)
c.\(\frac{2^5.7+2^5}{2^5.5^2-2^5.3}\)
d, \(\frac{3^4.5-3^6}{3^4.13+3^4}\)
a) \(\frac{25.9-25.17}{-8.80-8.10}=\frac{25.\left(9-17\right)}{-8.\left(80+10\right)}=\frac{25.\left(-8\right)}{-8.90}=\frac{5}{18}\)
b) \(\frac{48.12-48.15}{-3.270-3.30}=\frac{48.\left(12-15\right)}{-3.\left(270+30\right)}=\frac{48.\left(-3\right)}{-3.300}=\frac{4}{25}\)
c) \(\frac{2^5.7+2^5}{2^5.5^2-2^5.3}=\frac{2^5.\left(7+1\right)}{2^5.\left(5^2-3\right)}=\frac{2^5.8}{2^5.\left(25-3\right)}=\frac{2^5.8}{2^5.22}=\frac{4}{11}\)
d) \(\frac{3^4.5-3^6}{3^4.13+3^4}=\frac{3^4.\left(5-3^2\right)}{3^4.\left(13+1\right)}=\frac{3^4.\left(5-9\right)}{3^4.14}=\frac{3^4.\left(-4\right)}{3^4.14}=\frac{-2}{7}\)
Nguyễn Lương Bảo Tiên tại sao
3^4 × 5 - 3^6 lại = 3^4 (5 - 3^2) vậy
phần d ý
1.thực hiện phép tính
a.\(25.\left(\frac{-1}{5}\right)^3+\frac{1}{5}-2.\left(\frac{-1}{2}\right)^2-\frac{1}{2}\)
b.\(35^1_6:\left(\frac{-4}{5}\right)-46^1_6:\left(\frac{-4}{5}\right)\)
c.\(\left(\frac{-3}{4}+\frac{2}{5}\right):\frac{3}{7}+\left(\frac{3}{5}+\frac{-1}{4}\right):\frac{3}{7}\)
d.\(\frac{7}{8}:\left(\frac{2}{9}-\frac{1}{18}\right)+\frac{7}{8}.\left(\frac{1}{36}-\frac{5}{12}\right)\)
e.\(\frac{1}{6}+\frac{5}{6}.\frac{3}{2}-\frac{3}{2}+1\)
f.\(\left(-0,75-\frac{1}{4}\right):\left(-5\right)+\frac{1}{15}-\left(\frac{-1}{5}\right):\left(-3\right)\)
Bài 1:
a) Ta có: \(25\cdot\left(\frac{-1}{5}\right)^3+\frac{1}{5}-2\cdot\left(\frac{-1}{2}\right)^2-\frac{1}{2}\)
\(=25\cdot\frac{-1}{125}+\frac{1}{5}-2\cdot\frac{1}{4}-\frac{1}{2}\)
\(=-\frac{1}{5}+\frac{1}{5}-\frac{1}{2}-\frac{1}{2}\)
\(=\frac{-2}{2}=-1\)
b) Ta có: \(35\frac{1}{6}:\left(\frac{-4}{5}\right)-46\frac{1}{6}:\left(\frac{-4}{5}\right)\)
\(=\frac{211}{6}\cdot\frac{-5}{4}-\frac{277}{6}\cdot\frac{-5}{4}\)
\(=\frac{-5}{4}\cdot\left(\frac{211}{6}-\frac{277}{6}\right)\)
\(=\frac{-5}{4}\cdot\left(-11\right)=\frac{55}{4}\)
c) Ta có: \(\left(\frac{-3}{4}+\frac{2}{5}\right):\frac{3}{7}+\left(\frac{3}{5}+\frac{-1}{4}\right):\frac{3}{7}\)
\(=\frac{-7}{20}\cdot\frac{7}{3}+\frac{7}{20}\cdot\frac{7}{3}\)
\(=\frac{7}{3}\cdot\left(-\frac{7}{20}+\frac{7}{20}\right)=\frac{7}{3}\cdot0=0\)
d) Ta có: \(\frac{7}{8}:\left(\frac{2}{9}-\frac{1}{18}\right)+\frac{7}{8}\cdot\left(\frac{1}{36}-\frac{5}{12}\right)\)
\(=\frac{7}{8}\cdot6+\frac{7}{8}\cdot\frac{-7}{18}\)
\(=\frac{7}{8}\cdot\left(6+\frac{-7}{18}\right)\)
\(=\frac{7}{8}\cdot\frac{101}{18}=\frac{707}{144}\)
e) Ta có: \(\frac{1}{6}+\frac{5}{6}\cdot\frac{3}{2}-\frac{3}{2}+1\)
\(=\frac{1}{6}+\frac{15}{12}-\frac{3}{2}+1\)
\(=\frac{2}{12}+\frac{15}{12}-\frac{18}{12}+\frac{12}{12}\)
\(=\frac{11}{12}\)
f) Ta có: \(\left(-0,75-\frac{1}{4}\right):\left(-5\right)+\frac{1}{15}-\left(-\frac{1}{5}\right):\left(-3\right)\)
\(=\left(-1\right):\left(-5\right)+\frac{1}{15}-\frac{1}{15}\)
\(=\frac{1}{5}\)