= 249.17-249.111-17.3.111+17.51

 = 17.(249+51)-249.111-111.51

 = 17.300-111.(249+51)

 = 17.300-111.300

 = 300.(17-111)

 = 300.(-94)

 = -28200

Tk mk nha

-28200 nhé bn

​Tk mình đi nhé bn!

\(\dfrac{33}{38}:\dfrac{11}{19}=\dfrac{33\times19}{38\times11}=\dfrac{3\times1}{2\times1}=\dfrac{3}{2}\)

3phần2

7 x 17 x 125 = (8 x 125) x 17 = 1000 x 17 = 17000

4 x 37 x 25 = (25 x 4 ) x 7 = 100 x 7 = 700

43 x 27 + 93 x 43 + 57 x 81 + 69 x 57 = 43 x (27 + 93) + 57 x (81 +69) = 43 x 120 + 57 x 120 + 57x30 = 120 x (43 + 57) + 1710 = 12000 + 1710 = 13710 

a(17/4x12/7-2/7x17/4-3/7x17/4)x6/51

=[17/4x(12/7-2/7-3/7)]x6/51

=17/4x1x6/51

=17/4x6/51

=102/204=1/2

b,45x16-17/45x15+28

=15x3x16-17/45x15+28

=15x48-17/45x15+28

=15x2160/45-17/45x15+28

=15x(2160/45-17/45)+28

=15x2143/45+28

=2143/3+84/3

=2227/3

tính nhanh à,lên google search í

  (Người THÀNH CÔNG luôn có một lối đi riêng)

a: \(0.2=\dfrac{2}{10}\)

10>7

=>\(\dfrac{2}{10}< \dfrac{2}{7}\)

=>\(\dfrac{2}{7}>0.2\)

b: \(-\dfrac{1^5}{6}=\dfrac{-1}{6}=\dfrac{-3}{18}\)

\(\dfrac{8}{-9}=-\dfrac{16}{18}\)

mà -3>-16

nên \(-\dfrac{1^5}{6}>\dfrac{8}{-9}\)

c: \(\dfrac{2017}{2016}>1\)

\(1>\dfrac{2017}{2018}\)

Do đó: \(\dfrac{2017}{2016}>\dfrac{2017}{2018}\)

d: \(-\dfrac{249}{333}=\dfrac{-249:3}{333:3}=\dfrac{-83}{111}\)

e: \(\dfrac{5^1}{3}=\dfrac{5}{3}=\dfrac{15}{9}\)

\(\dfrac{4^8}{9}=\dfrac{65536}{9}\)

mà 15<65536

nên \(\dfrac{5^1}{3}< \dfrac{4^8}{9}\)

f: 13,589<13,612

36x3x111-36x3x111

=0 tk mk nha

36 x 333 - 108 x 111

= ( 36 x 3 ) x ( 333 : 3 ) - 108 x 111

= 108 x 111 - 108 x 111

= 0

36 x 333 - 108 x 111

= 12 x 111 - 108 x 111

= 111 x ( 108 - 12 )

= 111 x 96

= 10656

a) 1

b)99900

a) [ 45 * 16 - 17] : [45 * 15 + 28]

=  703 : 703

= 1 

b) [ 36 * 333 - 107 * 111] * 900

=  [ 11988 - 11877] * 900

=  111 * 900

= 99900

a là bằng 1

b là bằng 99 900

(2+4+6+...+100)x(36x333-108x111)=(2+4+6+...+100)x(36x3x111-108x111)

=(2+4+6+...+100)x(108x111-108x111)

=(2+4+6+...+100)x0

=0

\(\left(2+4+6+...+100\right)\left(36.333-108.111\right)=\left(2+4+6+...+100\right).\left[111\left(36.3-108\right)\right]=\left(2+4+6+...+100\right).0=0\)

(2+4+6+.......+100) (36 x 333 -108 X 111 )
=2x(1+2+3+......+50)[36x111(1x3-3x1)
=2x(1+2+3+......+50)(36x111x0)
=2x(1+2+3+......+50)x0
=0

   ( 2 + 4 + 6 + ....... + 100 ) ( 36 x 333 - 108 X 111 )
= 2 x ( 1 + 2 + 3 + ...... + 50 ) [36 x 111 ( 1 x 3 - 3 x 1 )
= 2 x ( 1 + 2 + 3 + ...... + 50 ) ( 36 x 111 x 0 )
= 2 x ( 1 + 2 + 3 + ...... + 50 ) x 0
= 0