1,11+0,19-13,2 / 2,06 + 0,54 - (1/3+1/2) : 2 = ?
(1,11+0,19-2,6):(2,06+0,54)-(1/2+1/3):2
( 1.11 + 0.19 - 2.6 ) : ( 2.06 + 0.54 ) - ( 1/2 + 1/3 ) : 2
= -1.3 : 2.6 - 5/6 : 2
= -1/2 - 5/12
= -11/12
= -11/12 ( bằng âm mười một phần mười hai )
Rút gọn A = (1,11+0,19-13*2)/(2,06+0,54)-(1/2+1/3)/2
Tinh :
a, ( 1,11+0,19-1,6):(2,06+0,54)-(1/2+1/3):2
b,-15,5.20,8+3,5.9,2-15,5.9,2+3,5.20,8
a: \(=\dfrac{1.3-1.6}{2.6}-\dfrac{5}{6}:2\)
\(=-\dfrac{3}{26}-\dfrac{5}{12}\)
\(=\dfrac{-83}{156}\)
b: \(=20.8\left(-15.5+3.5\right)+9.2\left(3.5-15.5\right)\)
\(=-12\left(20.8+9.2\right)\)
\(=-12\cdot30=-360\)
1,11+0,19-13x2
2,06+0,54
Tính bằng cách hợp lí:
\(\left(1,11+0,19-2,6\right):\left(2,06+0,54\right)-\left(\frac{1}{2}+\frac{1}{3}\right):2\)
Giúp mị với , mị cảm ơn
giúp mik nha
a>\(\frac{1,11+0,19-1,3.2}{2,06+0,54}-\left(\frac{1}{2}+\frac{1}{3}\right):2\)
b> (-15,5).20,8+3,5.9,2-15,5.9,2+3,5.20,8
tính
a)(1,11+0,19-2,6):(2,06+0,54)-(\(\frac{1}{2}+\frac{1}{3}\)):2
b)(\(2\frac{1}{3}+3,5\)):(\(-4\frac{1}{6}+3\frac{1}{7}\))+7,5
1. tìm x
a, 2x - \(\dfrac{1}{2}\) : \(\dfrac{3}{4}\) = \(\dfrac{12}{9}\)
b, x\(^2\) - 2 = 0
2. Cho
A = \(\dfrac{1,11+0,19-13.2}{2,06+0,54}\) - \(\left(\dfrac{1}{2}+\dfrac{1}{4}\right)\) : 2
B = \(\left(5\dfrac{7}{8}-2\dfrac{1}{4}-0,5\right)\) : \(2\dfrac{23}{26}\)
a, Rút gọn A, B
b, Tìm x ϵ Z để A < x < B
a)
=\(2x-\dfrac{1}{2}=\dfrac{12}{9}\cdot\dfrac{3}{4}=1\)
=\(2x=1+\dfrac{1}{2}=1.5\)
=\(x=1.5:2=0.75\)
b)
=\(x^2=0+2=2\)
TH1:\(x=2\)
TH2:\(x=-2\)
Bài 1:
a: \(2x-\dfrac{1}{2}:\dfrac{3}{4}=\dfrac{12}{9}\)
=>\(2x-\dfrac{1}{2}\cdot\dfrac{4}{3}=\dfrac{4}{3}\)
=>\(2x=\dfrac{4}{3}+\dfrac{2}{3}=\dfrac{6}{3}=2\)
=>x=2/2=1
b: \(x^2-2=0\)
=>\(x^2=2\)
=>\(\left[{}\begin{matrix}x=\sqrt{2}\\x=-\sqrt{2}\end{matrix}\right.\)
Bài 2:
a: \(A=\dfrac{1,11+0,19-13\cdot2}{2,06+0,54}-\left(\dfrac{1}{2}+\dfrac{1}{4}\right):2\)
\(=\dfrac{1,3-26}{2,6}-\dfrac{3}{4}:2\)
\(=-9,5-\dfrac{3}{8}=-\dfrac{79}{8}\)
\(B=\left(5\dfrac{7}{8}-2\dfrac{1}{4}-0,5\right):\left(2\dfrac{23}{26}\right)\)
\(=\left(5+\dfrac{7}{8}-2-\dfrac{1}{4}-\dfrac{1}{2}\right):\dfrac{75}{26}\)
\(=\left(3+\dfrac{1}{8}\right)\cdot\dfrac{26}{75}=\dfrac{25}{8}\cdot\dfrac{26}{75}=\dfrac{13}{12}\)
b: A<x<B
=>\(-\dfrac{79}{8}< x< \dfrac{13}{12}\)
mà \(x\in Z\)
nên \(x\in\left\{-9;-8;...;0;1\right\}\)
Bài1.Tính hợp lí:
a) (1,11+0,19-2,6):(2,06+0,54)-(\(\dfrac{1}{2}+\dfrac{1}{3}\)):2
b) (2\(\dfrac{1}{3}\)+3,5):(-4\(\dfrac{1}{6}+3\dfrac{1}{7}\))+7,5
a: \(=\left(1.3-2.6\right):\left(2.6\right)-\dfrac{5}{6}:2\)
\(=\dfrac{-1.3}{2.6}-\dfrac{5}{12}\)
\(=\dfrac{-1}{2}-\dfrac{5}{12}=\dfrac{-11}{12}\)
b: \(=\left(\dfrac{7}{3}+\dfrac{7}{2}\right):\left(-\dfrac{25}{6}+\dfrac{22}{7}\right)+\dfrac{15}{2}\)
\(=\dfrac{35}{6}:\dfrac{-175+132}{42}+\dfrac{15}{2}\)
\(=\dfrac{-35}{6}\cdot\dfrac{42}{43}+\dfrac{15}{2}=\dfrac{155}{86}\)