A = / x^5 - 32 / - 17

Vì 2^5 = 32 nên / x^5 - 32 / có giá trị nhỏ nhất là 0

Vậy GTNN của A là 0 - 17 = -17

B = / x - 9 / - x + 15

/ x - 9 / đạt GTNN khi x = 9 .

Vậy GTNN của B là 0 - 9 + 15 = 6

C = / x - 5 / + x - 3

/ x - 5 / đạt GTNN khi x = 5

Vậy GTNN của C là 0 + 5 - 3 = 2

D = 17 - / / x / - 2 /

Muốn D càng lớn thì / / x / - 2 / ( hay còn gọi là số trừ trong phép tính trên ) phải càng nhỏ .

GTNN của / / x / - 2 / đạt khi x thuộc 2 ; -2

Vậy GTLN của D là 17 - 0 = 17

min vs max là cái j đấy ... > . < ...

a, -121 - [-35 - x] = 50

<=> -35 - x = -121 - 50

<=> -35 - x =  -171

<=> x = -171 + [-35] = -206

Vậy x = -206

b, 17 + x - [352 - 400] = -32

<=> 17 + x - [-48] = -32

<=> 17 + x + 48 = -32

<=> 17 + x = -32 - 48

<=> 17 + x = -80

<=> x = -80 - 17

<=> x = -97

Vậy x = -97

c, 2130 - [x + 130] + 72 = -64

<=> 2130 - [x + 130] = -64 - 72

<=> 2130 - [x + 130] = -136

<=> x + 130 = 2130 - [-136]

<=> x + 130 = 2130 + 136

<=> x + 130 = 2266

<=> x = 2266 - 130 = 2136

d, |x| - 5 = -1

<=> |x| = -1 + 5

<=> |x| = 4

<=> x = 4 hoặc x = -4

e, |x+ 2| - 12 = -1

<=> |x + 2| = -1 + 12

<=> |x + 2| = 11

<=> x + 2 = 11 hoặc x + 2 = -11

<=> x = 11 - 2 hoặc x = -11 - 2

<=> x = 9 hoặc x = -13

f,g Tương tự

a) -121 - (-35 - x) = 50

-121 + 35 + x = 50

x - 86 = 50

x = 50 + 86

x = 136

b) 17 + x - (352 - 400) = -32

17 + x - 352 + 400 = -32

x + 65 = -32

x = -32 - 65

x = -97

c) 2130 - (x + 130) + 72 = -64

2130 - x - 130 + 72 = -64

2072 - x = -64

-x = -64 - 2072

-x = -2136

x = 2136

d) |x| - 5 = -1

|x| = -1 + 5

|x| = 4

x = 4; -4

e) |x + 2| - 12 = -1

|x + 2| = -1 + 12

|x + 2| = 11

x + 2 = 11; -11

x + 2 = 11 hoặc x + 2 = -11

x = 11 - 2          x = -11 - 2

x = 9                 x = -13

f) 135 - |9 - x| = 35

-|9 - x| = 35 - 135

-|9 - x| = -100

|9 - x| = 100

9 - x = 100; -100

9 - x = 100 hoặc 9 - x = -100

x = 100 + 9            x = -100 + 9

x = 109                  x = -91

a,48:(7x-15)=8

7x-15=6

7x=21

x=3

b,100-3(5-x)=73

3(5-x)=27

5-x=9

x=-4

c,[(x+32)-17]*2+8=50

[(x+32)-17]*2=42

(x+32)-17=21

x+32=38

x=6

a)48:(7x-15)=8

         (7x-15)=48:8

         (7x-15)=6

                7x=6+15

                 7x=21

                   x=21:7

                   x=3

b)100-3(5-x)=73

          3(5-x)=100-73

         3(5-x)=27

            5-x=27:3

             5-x=9

                x=5-9

                x=-4

c)[(x+32)-17]x2+8=50

   [(x+32)-17]x2=50+8=58

   [(x+32)-17]=58:2

          x+32   =29+17

          x         =46-32

         x           =14

`a) 3-5+(-x+3)=6`

`=>5+(-x+3)=3-6`

`=>5+(-x+3)=-3`

`=>-x+3=-3-5`

`=>-x+3=-8`

`=>-x=-8-3`

`=>-x=-11`

`=>x=11`

__

`b)(-4-x)+(4-15)=-15`

`=>(-4-x)+-11=-15`

`=>-4-x=-15-(-11)`

`=>-4-x=-15+11`

`=>-4-x=-4`

`=>x=-4-(-4)`

`=>x=-4+4`

`=>x=0`

`c)(11+x)-(-11-9)=32`

`=>(11+x)-(-20)=32`

`=>(11+x)+20=32`

`=>11+x=32-20`

`=>11+x=12`

`=>x=12-11`

`=>x=1`

`a)3-5+(-x+3)=6`

`5+(-x+3)=3-6`

`5+(-x+3)=-3`

`-x+3=-3-5`

`-x+3=-8`

`-x=-8-3`

`-x=-11`

`x=11`

`b,(-4-x)+(4-15)=-15`

`(-4-x)+(-11)=-15`

`-4-x=-15-(-11)`

`-4-x=-15+11`

`-4-x=-4`

`x=-4-(-4)`

`x=-4+4`

`x=0`

`c)(11+x)-(-11-9)=32`

`(11+x)-(-20)=32`

`(11+x)+20=32`

`11+x=32-20`

`11+x=12`

`x=12-11`

`x=1`

a ) 3 − 5 + ( − x + 3 ) = 6 ⇒ 5 + ( − x + 3 ) = 3 − 6 ⇒ 5 + ( − x + 3 ) = − 3 ⇒ − x + 3 = − 3 − 5 ⇒ − x + 3 = − 8 ⇒ − x = − 8 − 3 ⇒ − x = − 11 ⇒ x = 11 __ b ) ( − 4 − x ) + ( 4 − 15 ) = − 15 ⇒ ( − 4 − x ) ± 11 = − 15 ⇒ − 4 − x = − 15 − ( − 11 ) ⇒ − 4 − x = − 15 + 11 ⇒ − 4 − x = − 4 ⇒ x = − 4 − ( − 4 ) ⇒ x = − 4 + 4 ⇒ x = 0 c ) ( 11 + x ) − ( − 11 − 9 ) = 32 ⇒ ( 11 + x ) − ( − 20 ) = 32 ⇒ ( 11 + x ) + 20 = 32 ⇒ 11 + x = 32 − 20 ⇒ 11 + x = 12 ⇒ x = 12 − 11 ⇒ x = 1

1. \(x-8+32=68\)

\(x-8=68-32\)

\(x-8=36\)

\(x=36+8\)

\(x=44\)

_____

2. \(x+8+32=68\)

\(x+8=68-32\)

\(x+8=36\)

\(x=36-8\)

\(x=28\)

_____

3. \(98-x+34=43\)

\(98-x=43-34\)

\(98-x=9\)

\(x=98-9\)

\(x=89\)

_____

4. \(98+x-34=43\)

\(98+x=43+34\)

\(98+x=77\)

\(x=77-98\)

\(x=-21\)

_____

5. \(x:5:4=800\)

\(x:5=800.4\)

\(x:5=3200\)

\(x=3200.5\)

\(x=16000\)

_____

6. \(18+x=384:8\)

\(18+x=48\)

\(x=48-18\)

\(x=30\)

_____

7. \(\left(84,6-2\times x\right):3,02=5,1\)

\(84,6-2.x=5,1.3,02\)

\(84,6-2.x=15,402\)

\(2.x=84,6-15,402\)

\(2.x=69,198\)

\(x=69,198:2\)

\(x=34,599\)

_____

8. \(x\times5=120:6\)

\(x.5=20\)

\(x=20:5\)

\(x=4\)

_____

9. \(\left(15\times24-x\right):0,25=100:0,25\)

\(\left(15.24-x\right):0,25=400\)

\(15.24-x=400.0,25\)

\(15.24-x=100\)

\(360-x=100\)

\(x=360-100\)

\(x=260\)

1,x-8+32=68

=>x-8=68-32=36

=>x=36+8=42

2,x+8+32=68

=>x+8=68-32=36

=>x=36-8=28

3,98-x+34=43

=>98-x=43-34=9

=>x=98-9=89

4,98+x-34=43

=>98+x=43+34=77

=>x=77-98=-21

5,x:5:4=800

=>x:20=800

=>x=800x20=16000

6,18+x=384:8=48

=>x=48-18=30

7,(84,6-2x):3,02=5,1

=>84,6-2x=5,1x3,02=15,402

=>2x=84,6-15,402=69,198

=>x=69,198:2=34,599

8,5x=120:6=20

=>x=20:5=4

9,(15x24-x):0,25=100:0,25=400

=>360-x=400x0,25=100

=>x=360-100=260.

1. \(...\Rightarrow x+24=68\Rightarrow x=68-24=44\)

2. \(...\Rightarrow x+40=68\Rightarrow x=68-40=28\)

3. \(...\Rightarrow3^{2\left(8+x\right)}=9=3^2\Rightarrow2\left(8+x\right)=2\Rightarrow8+x=1\Rightarrow x=-7\)

4. \(...\Rightarrow3^{2\left(8+x\right)}=77\) (bạn xem lại đề)

5. \(...\Rightarrow x:5=800.4\Rightarrow x:5=3200\Rightarrow x=3200.5=16000\)

6. \(...\Rightarrow18+x=48\Rightarrow x=48-18=30\)

7. \(...\Rightarrow84,6-2x=5,1.3,02=15,402\Rightarrow2x=84,6-15,402\Rightarrow2x=69,198\Rightarrow x=34,599\)

8. \(...\Rightarrow5.x=20\Rightarrow x=20:5=4\)

9. \(\left(360-x\right):0,25=400\Rightarrow360-x=400.0,25=100\Rightarrow x=400-100=300\)

\(\left(\frac{3}{20}+\frac{1}{20}-x\right):\frac{32}{9}=\frac{21}{128}\)

\(\Leftrightarrow\frac{4}{20}-x=\frac{21}{128}.\frac{32}{9}\)

\(\Leftrightarrow\frac{1}{5}-x=\frac{7}{12}\)

\(\Leftrightarrow x=\frac{1}{5}-\frac{7}{12}\)

\(\Leftrightarrow x=-\frac{23}{60}\)

Vậy \(x=\frac{-23}{60}\)

Bài làm

\(\left(\frac{3}{20}+\frac{1}{20}-x\right):\frac{32}{9}=\frac{21}{128}\)

\(\left(\frac{3}{20}+\frac{1}{20}-x\right)=\frac{21}{128}.\frac{32}{9}\)

\(\frac{4}{20}-x=\frac{7}{4}.\frac{1}{3}\)

\(\frac{4}{20}-x=\frac{7}{12}\)

\(x=\frac{4}{20}-\frac{7}{12}\)

\(x=\frac{12}{60}-\frac{35}{60}\)

\(x=-\frac{23}{60}\)

Vậy \(x=-\frac{23}{60}\)

\(x=-\frac{37}{15}\)