a: =17/25(13/19+6/19)=17/25

b: \(=\dfrac{47}{19}\cdot\dfrac{32}{15}-\dfrac{47}{19}\cdot\dfrac{17}{15}=\dfrac{47}{19}\)

`17/25xx(13/19+6/19)`

`17/25xx1`

`17/25`

`a)17/25xx13/19+17/25xx6/19`

`=17/25xx(13/19+6/19)`

`=17/25xx19/19=17/25`

`b)47/19:15/32-47/19:15/17`

`=47/19xx32/15-47/19xx17/15`

`=47/19xx(32/15-17/15)`

`=47/19xx15/15=47/19`

Lời giải:

dan3yt3t3

-2x-3.(x-17)=34-2(-x+25)

-2x-3x+51=34+2x-50

-2x-3x+51-34-2x+50=0

-7x+67=0

-7x=-67

x=\(\frac{67}{7}\)

\(\left(x+\dfrac{1}{5}\right)^2=\dfrac{9}{25}\)

\(\left(x+\dfrac{1}{5}\right)^2=\left(\dfrac{3}{5}\right)^2\)

➩ \(x+\dfrac{1}{5}=\dfrac{3}{5}\)

    \(x=\dfrac{3}{5}-\dfrac{1}{5}\)

   \(x=\dfrac{2}{5}\)

\(\left(x+\frac{1}{5}\right)^2=\frac{26}{25}-\frac{17}{25}\)

\(\left(x+\frac{1}{5}\right)^2=\frac{9}{25}\)

\(\left(x+\frac{1}{5}\right)^2=\left(\frac{3}{5}\right)^2\)

\(x+\frac{1}{5}=\frac{3}{5}\)

\(x=\frac{3}{5}-\frac{1}{5}\)

\(x=\frac{2}{5}\)

vậy \(x=\frac{2}{5}\)

\(\left(x+\frac{1}{5}\right)^2+\frac{17}{25}=\frac{26}{25}\)

\(\left(x+\frac{1}{5}\right)^2=\frac{26}{25}-\frac{17}{25}\)

\(\left(x+\frac{1}{5}\right)^2=\frac{9}{25}\)

\(\left(x+\frac{1}{5}\right)^2=\left(\frac{3}{5}\right)^2\)

\(x+\frac{1}{5}=\frac{3}{5}\)

\(x=\frac{3}{5}-\frac{1}{5}\)

\(x=\frac{2}{5}\)

1) \(=\left(\frac{3}{5}+\frac{2}{5}\right).\frac{6}{11}\)

\(=1.\frac{6}{11}\)

\(=\frac{6}{11}\)

2)\(\frac{17}{25}.\left(\frac{11}{19}+\frac{6}{19}+\frac{2}{19}\right)\)

\(=\frac{17}{25}.1\)

\(=\frac{17}{25}\)

2.\(\frac{17}{25}.\frac{11}{19}+\frac{17}{25}.\frac{6}{19}+\frac{17}{25}.\frac{2}{19}=\frac{17}{25}\left(\frac{11}{19}+\frac{6}{19}+\frac{2}{19}\right)\\ =\frac{17}{25}.1\\ =\frac{17}{25}\)

2*(x-5)-17=25

=>2*(x-5)=25+17

=>2*(x-5)=42

=>x-5=42:2

=>x-5=21

=>x=21+5

=>x=26.

3*(x+7)-15=27

=>3*(x+7)=27+15

=>3*(x+7)=42

=>x+7=42:3

=>x+7=14

=>x=14-7

=>x=7

2 nhan (x-5)-17=25

2 nhan (x-5)=25+17

2 nhân(x+5)=42

           x-5=42:2

           x-5+21

           x=21+5

            x=26

3 nhân(x+7)-15=27

3 nhân(x+7)     =27+15

3 nhân(x+7)      =42

           (x+7)     =42:3

           (x+7)      =14

              x=14-7

               x=7

a) Ta có: \(x-12=\left(-9\right)-15\)

\(\Rightarrow x-12=-24\)

\(\Rightarrow x=-12\)

b) \(2-x=17-\left(-5\right)\)

\(\Rightarrow2-x=22\)

\(\Rightarrow x=2-22\)

\(\Rightarrow x=-20\)

c) \(11-\left(15+11\right)=x-\left(25-9\right)\)

\(\Rightarrow-15=x-16\)

\(\Rightarrow x=1\)

d) \(x-\left(17-x\right)=x-7\)

\(\Rightarrow x-17+x=x-7\)

\(\Rightarrow x+x-x=-7+17\)

\(\Rightarrow x=10\)

e) \(9-25=\left(7-x\right)-\left(25+7\right)\)

\(\Rightarrow9-25=7-x-25-7\)

\(\Rightarrow-16=-25-x\)

\(\Rightarrow x=-9\)

g) \(x-13=21-x\)

\(\Rightarrow x+x=21+13\)

\(\Rightarrow2x=34\)

\(\Rightarrow x=17\)

a, x - 12 = ( -9 ) - 15 

x - 12 = -24

x = -24 + 12

x = -12

b, 2 - x = 17 - ( -5 )

2 - x = 22

x = 2 - 22

x = -20

c, 11 - ( 15 + 11 ) = x - ( 25 - 9 )

11 - 26 = x - 16

-15 = x - 16

x = -15 + 16 

x = 1

d, x - ( 17 - x ) = x - 7

x - 17 + x = x - 7

x + x - 17 = x - 7

x + x - x = -7 + 17

x = 10

e.9 - 25 = ( 7- x ) - ( 25 + 7 )

-16 = ( 7 - x ) -32

7 - x = -32 + 16 

7 - x = 16

x = 7 - 16

x= -9

g, x - 13 = 21 - x

x + x = 21 + 13

2x = 44

x = 44 : 2

x=22

A= -12

B=-20

C=1

D=17

E=-9

G=17