[ 1- 1/2] nhân [1- 1/3] nhân [1- 1/4] nhân... nhân [1-1/ 2014] nhân [ 1- 1/2015
[1-1/2] nhân [1-1/3] nhân [1-1/4] nhân [1-1/5] nhân ... nhân [1-1/2014] nhân [1- 1/2015]
A=(1 trừ 1/2 ) nhân ( 1 trừ 1/3 ) nhân ( 1 trừ 1/4 ) nhân ( 1 trừ 1/5 ) nhân ....... nhân ( 1 trừ 1/2014 ) nhân ( 1 trừ 1/2015 )
A = (1 - \(\frac{1}{2}\)) x (1 - \(\frac{1}{3}\)) x (1 - \(\frac{1}{4}\)) x (1 - \(\frac{1}{5}\)) x ... x (1 - \(\frac{1}{2014}\)) x (1 - \(\frac{1}{2015}\))
A = \(\frac{1}{2}\)x \(\frac{2}{3}\) x \(\frac{3}{4}\) x \(\frac{4}{5}\) x ... x \(\frac{2013}{2014}\)x \(\frac{2014}{2015}\)
A = \(\frac{1x2x3x4x...x2013x2014}{2x3x4x5x...x2014x2015}\)
A = \(\frac{1}{2015}\)
Vậy A = \(\frac{1}{2015}\)
~~~
\(A=\left(1-\frac{1}{2}\right)\left(1-\frac{1}{3}\right)\left(1-\frac{1}{4}\right)\left(1-\frac{1}{5}\right)...\left(1-\frac{1}{2014}\right)\left(1-\frac{1}{2015}\right)\)
\(A=\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{3}{4}\cdot\frac{4}{5}\cdot...\cdot\frac{2013}{2014}\cdot\frac{2014}{2015}\)
\(A=\frac{1\cdot2\cdot3\cdot4\cdot...\cdot2013\cdot2014}{2\cdot3\cdot4\cdot5\cdot...\cdot2014\cdot2015}\)
\(A=\frac{1}{2015}\)
tính:(1+1/1 nhân 3)(1+1/2 nhân 4)(1+1/3 nhân 5)(1+1/4 nhân 6)...(1+1/2013 nhân 2015)
1 nhân 2 cộng 1/2 nhân 3 cộng 1/3 nhân 4 cộng ......... cộng 1/2013 nhân 2014
a) (2 và 4/5= 3 và 2/5)+(1 và 1/5-2/5)+3
b) 107,35-( 16,85+284,745:12,3)
c) 2015 nhân 2015-2014 nhân 2016
2015 nhân 2017 trừ 1/2014 công 2015 nhân 2016 nhan 2/3
\(\frac{2015\cdot2017-1}{2014+2015\cdot2016}\)\(\cdot\frac{2}{3}\)
\(=\frac{2015\cdot\left(2016+1\right)-1}{2014+2015\cdot2016}\cdot\frac{2}{3}\)
\(=\frac{2015\cdot2016+\left(2015-1\right)}{2014+2015\cdot2016}\cdot\frac{2}{3}\)
\(=\frac{2015\cdot2016+2014}{2014+2015\cdot2016}\cdot\frac{2}{3}\)
\(=1\cdot\frac{2}{3}\)
\(=\frac{2}{3}\)
6772415 nha!
Mình tính bằng máy tính CASIO đấy nhé.Đúng 10000000000000000000000000000000000000000000000000000000000000000000.....%
Tính nhanh nếu có thể
a. 2017/2016 nhân 3/4 trừ 1/2016 nhân 0,75
b.1/2 nhân 2015/2016 cộng 1/3 nhân 2015/2016 trừ 2015/2016 nhân 5/6
a)\(=\frac{2017}{2016}.\frac{3}{4}-\frac{1}{2016}.\frac{3}{4}\)
\(=\frac{3}{4}\left(\frac{2017}{2016}-\frac{1}{2016}\right)\)
\(=\frac{3}{4}.1\)
\(=\frac{3}{4}\)
b)\(=\frac{2015}{2016}\left(\frac{1}{2}+\frac{1}{3}-\frac{5}{6}\right)\)
\(=\frac{2015}{2016}.0\)
\(=0\)
TÍNH:
A= 1 trừ 2 phần 1 nhân 4 trừ 2 phần 4 nhân 7 trừ 2 phần 2014 nhân 2015
HOẶC
\(A=1-\frac{2}{1.4}-\frac{2}{4.7}-\frac{2}{2014.2015}\)
2/5 nhân 1/7 + 2/7 nhân 2/5
x + 1/2 nhân 1/3 = 3/4
(1-1/2) nhân (1 - 1/3) nhân ( 1 - 1/4) nhân ... nhân (1 - 1/2020) + x =1/2
\(\dfrac{2}{5}\times\dfrac{1}{7}+\dfrac{2}{7}\times\dfrac{2}{5}\)
\(=\dfrac{2}{5}\times\left(\dfrac{1}{7}+\dfrac{2}{7}\right)\)
\(=\dfrac{2}{5}\times\dfrac{3}{7}\)
\(=\dfrac{6}{35}\)
\(x+\dfrac{1}{2}\times\dfrac{1}{3}=\dfrac{3}{4}\)
\(x+\dfrac{1}{6}=\dfrac{3}{4}\)
\(x=\dfrac{9}{12}-\dfrac{2}{12}\)
\(x=\dfrac{7}{12}\)
\(\left(1-\dfrac{1}{2}\right)\times\left(1-\dfrac{1}{3}\right)\times\left(1-\dfrac{1}{4}\right)\times...\times\left(1-\dfrac{1}{2020}\right)+x=\dfrac{1}{2}\)
\(\dfrac{1}{2}\times\dfrac{2}{3}\times\dfrac{3}{4}\times...\times\dfrac{2019}{2020}+x=\dfrac{1}{2}\)
\(\dfrac{1}{2020}+x=\dfrac{1}{2}\)
\(x=\dfrac{1}{2}-\dfrac{1}{2020}\)
\(x=\dfrac{1010}{2020}-\dfrac{1}{2020}\)
\(x=\dfrac{1009}{2020}\)
\(\dfrac{2}{5}\times\dfrac{1}{7}+\dfrac{2}{7}\times\dfrac{2}{5}\)
\(=\dfrac{2}{5}\times\left(\dfrac{1}{7}+\dfrac{2}{7}\right)\)
\(=\dfrac{2}{5}\times\dfrac{3}{7}\)
\(=\dfrac{6}{35}\)
\(x+\dfrac{1}{2}\times\dfrac{1}{3}=\dfrac{3}{4}\)
\(\Rightarrow\dfrac{1}{2}\times\dfrac{1}{3}=\dfrac{3}{4}-x\)
\(\Rightarrow\dfrac{3}{4}-x=\dfrac{1}{6}\)
\(\Rightarrow x=\dfrac{3}{4}-\dfrac{1}{6}=\dfrac{7}{12}\)
\(\left(1-\dfrac{1}{2}\right)\times\left(1-\dfrac{1}{3}\right)\times\left(1-\dfrac{1}{4}\right)\times...\times\left(1-\dfrac{1}{2020}\right)+x=\dfrac{1}{2}\)
\(\Rightarrow\dfrac{1}{2}\times\dfrac{2}{3}\times\dfrac{3}{4}\times...\times\dfrac{2019}{2020}+x=\dfrac{1}{2}\)
\(\Rightarrow\dfrac{1\times2\times3\times4\times...\times2019}{2\times3\times4\times5\times...\times2020}+x=\dfrac{1}{2}\)
\(\Rightarrow\dfrac{1}{2020}+x=\dfrac{1}{2}\)
\(\Rightarrow x=\dfrac{1}{2}-\dfrac{1}{2020}=\dfrac{1009}{2020}\)