A=\(\dfrac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}=\dfrac{11.3^{29}-3^{29}.3}{2^2.3^{28}}=\dfrac{3^{29}.\left(11-3\right)}{2^2.3^{28}}=\dfrac{3^{29}.2^3}{2^2.3^{28}}=3.2=6\)

\(A=\dfrac{11\cdot3^{22}\cdot3^7-9^{15}}{\left(2\cdot3^{14}\right)^2}=\dfrac{11\cdot3^{29}-3^{30}}{2^2\cdot3^{28}}\)

\(=\dfrac{3^{29}\cdot2^3}{3^{28}\cdot2^2}=3\cdot2=6\)

ta có    \(\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}=\frac{11.3^{29}-\left(3^2\right)^{15}}{2^2.\left(3^{14}\right)^2}\)

=  \(\frac{11.3^{29}-3^{30}}{2^2.3^{28}}=\frac{3^{29}\left(11-3\right)}{2^2.3^{28}}\)

=   \(\frac{3^{29}.2^3}{2^2.3^{28}}=3.2=6\)

A = -2 nhé , 

gợi ý các bạn chọn (k) đúng cho mình.

là ơn giúp với 

help me 

help me !

help me 

6

ai trả lời thì trả lời chi tiết đi

mình đang cần gấp

a ) \(\frac{11\cdot3^{22}\cdot3^7-9^{15}}{\left(2\cdot3^{14}\right)^2}=\frac{11\cdot3^{29}-\left(3^2\right)^{15}}{2^2\cdot3^{28}}\)

\(=\frac{3^{28}\left(11\cdot3-3^2\right)}{2^2\cdot3^{28}}=\frac{33-9}{4}=\frac{24}{4}=6\)

b ) \(27^{16}\div9^{10}\)

\(=\left(3^3\right)^{16}\div\left(3^2\right)^{10}\)

\(=3^{48}\div3^{20}\)

\(=3^{48-20}\)

\(=3^{28}\)

Bg

a) \(\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)

= \(\frac{11.3^{22}.3^7-3^{30}}{2^2.3^{28}}\)

= \(\frac{11.3^{29}-3.3^{29}}{4.3^{28}}\)

= \(\frac{8.3^{29}}{4.3^{28}}\)

= \(\frac{2.3}{1.1}\)

= 6

b) 27¹⁶ ÷ 9¹⁰ 

= 3^3.16 ÷ 3^2.10 

= 3⁴⁸ ÷ 3²⁰ 

= 3^{48 - 20} 

= 3²⁸