Ta có:

Lời giải:

Ta có:

Lời giải :

      Ta có :

 \(\frac{16}{81}\)\(=\)\(\left(\frac{4}{9}\right)^2\)\(=\)\(\left(\frac{-4}{9}\right)^2\)\(=\)\(\left(\frac{2}{3}\right)^4\)\(=\)\(\left(\frac{-2}{3}\right)^4\)

\(\dfrac{16}{81}=\left(\dfrac{2}{3}\right)^4\)

\(\dfrac{16}{81}=\left(-\dfrac{4}{9}\right)^2\)

\(\dfrac{16}{81}=\left(\dfrac{2}{3}\right)^4\)

Trả lời :

\(\frac{16}{18}=\frac{2^4}{3^4}=\left(\frac{2}{3}\right)^4\)

~ Học tốt ~

Bn ơi sai đề r pk là \(\frac{16}{81}\) chứ

Trả lời :

\(\frac{16}{18}=\frac{2^4}{3^4}=\left(\frac{2}{3}\right)^4\)

- Study well -

Cách viết khác : \(\frac{16}{81}=\frac{2^4}{3^4}=\left(\frac{2}{3}\right)^4\)

Chúc bạn học tốt ^^

\(\left(\frac{16}{81}\right)=\left(\frac{2}{3}\right)^4\)

\(\frac{16}{81}=\left(\frac{-4}{-9}\right)^2=\left(\frac{2^2}{3^2}\right)^2=\left(\frac{\left(-2\right)^4}{\left(-3\right)^4}\right)=...\)

\(\frac{16}{81}=\frac{2^4}{3^4}=\left(\frac{2}{3}\right)^4\)

\(\frac{25}{9}=\left(\frac{5}{3}\right)^2\)

\(\dfrac{16}{81}=\left(\dfrac{4}{9}\right)^2=\left(\dfrac{2}{3}\right)^4\)

\(\dfrac{16}{81}=\left(\dfrac{-4}{-9}\right)^2=\left(\dfrac{-2}{-3}\right)^4\)

\(\dfrac{16}{81}=\left(\dfrac{-4}{9}\right)^2=\left(\dfrac{-2}{3}\right)^4\)

\(\dfrac{16}{81}=\left(\dfrac{4}{-9}\right)^2=\left(\dfrac{2}{-3}\right)^4\)

Một số cách viết khác

\(\dfrac{16}{81}=\left(\dfrac{4}{9}\right)^2=\left(-\dfrac{4}{9}\right)^2=\left(\dfrac{2^2}{3^2}\right)^2=...\)

\(\frac{16}{81}=\left(\frac{2}{3}\right)^4\)

\(\frac{16}{81}=\left(-\frac{4}{9}\right)^2=\left(\frac{2}{3}\right)^4=\left(-\frac{2}{3}\right)^4\)

\(\frac{16}{81}=\left(\frac{-4}{9}\right)^2=\left(\frac{2}{3^{ }}\right)^4=\left(\frac{-2}{3^{ }}\right)^4\)