( x + 4 / 2010 + 1 ) + ( x + 3 / 2011 + 1 ) = ( x + 2 / 2012 + 1 ) + ( x + 1 / 2013 + 1 ) ! lm ơn giúp mik với
tìm x,biet(1/2+1/3+.............+1/2012+1/2013).x=2012/1+2011/2+2010/3+......+2/2011+1/2012
Tìm x biết (1/2+1/3+...+1/2012+1/2013).x = 2012/1+2011/2+2010/3+...+2/2011+1/2012
tìm x (1/2+1/3+...+1/2013) *x= 2012 +2011/2+2010/3+...+2/2011+1/2012
tìm x biết ( 1/2 + 1/3 + ... + 1/2012 + 1/2013 ) .x = 2012/1 + 2011/2 + 2010/3 + ... + 2/2011 + 1/2012
a)2^x+2^x+1+2^x+2+2^x+3=480
b)(1/2+1/3+...+1/2012+1/2013)*x=2012/1+2011/2+2010/3+..+2/2011+1/2012
tìm X biết : ( 1 / 2 + 1/3 + ........+ 1 /2012 + 1/2013 ) . x = 2012/1 + 2011/2 + 2010 /3 + .....+2/2011+1/2012
(1/2+1/3+....+1/2012+1/2013)*x=2012/1+2011/2+2010/3+...+2/2011+1/2012
\(\left(\frac{1}{2}+\frac{1}{3}+...+\frac{1}{2013}\right).x=\frac{2012}{1}+\frac{2011}{2}+\frac{2010}{3}+...+\frac{1}{2012}\)
x+1/2013 + x+2/2012=x+3/2011 + x+4/2010
x+1/2013+1+x+2/2012+1=x+3/2011+1+x+4/2010+1
x+1+2013/2013+x+2+2012/2012=x+3+2011/2011+x+4+2010/2010
x+2014/2013+x+2014/2012-x+2014/2011-x+2014/2010=0
(x+2014)(1/2013+1/2012-1/2011-1/2010)=0
x+2014=0
x=-2014
\(\frac{x+1}{2013}+1+\frac{x+2}{2012}+1=\frac{x+3}{2011}+1+\frac{x+4}{2010}+1\)
\(\Rightarrow\frac{x+2014}{2013}+\frac{x+2014}{2012}=\frac{x+2014}{2011}+\frac{x+2014}{2010}\)
\(\Rightarrow\left(x+2014\right)\left(\frac{1}{2013}+\frac{1}{2012}-\frac{1}{2011}-\frac{1}{2010}\right)=0\)
\(\Rightarrow\left(x+2014\right)=0\)
\(\Rightarrow x=-2014\)
\(\dfrac{x+4}{2010}\)+\(\dfrac{x+3}{2011}\)=\(\dfrac{x+2}{2012}\)+\(\dfrac{x+1}{2013}\)
\(\dfrac{x+4}{2010}+\dfrac{x+3}{2011}=\dfrac{x+2}{2012}+\dfrac{x+1}{2013}\)
\(\left(\dfrac{x+4}{2010}+1\right)+\left(\dfrac{x+3}{2011}+1\right)=\left(\dfrac{x+2}{2012}+1\right)+\left(\dfrac{x+1}{2013}+1\right)\)
\(\dfrac{x+2014}{2010}+\dfrac{x+2014}{2011}-\dfrac{x+2014}{2012}-\dfrac{x+2014}{2013}=0\)
\(\left(x+2014\right)\times\left(\dfrac{1}{2010}+\dfrac{1}{2011}-\dfrac{1}{2012}-\dfrac{1}{2013}\right)=0\)
Vì \(\dfrac{1}{2010}+\dfrac{1}{2011}-\dfrac{1}{2012}-\dfrac{1}{2013}\ne0\)
=> \(x+2014=0\)
\(x=0-2014\)
\(x=-2014\)