cho 1 vé báo cáo

a: ƯCLN(40;24)=8

ƯC(40;24)=Ư(8)={1;2;4;8}

b: UCLN(80;144)=16

UCLN(80;144)={1;2;4;8;16}

c: UCLN(9;18;72)=9

ƯC(9;18;72)={1;3;9}

d: ƯCLN(25;55;75)=5

ƯC(25;55;75)={1;5}

\(a,40=2^3.5\\ 24=2^3.3\\ \Rightarrow UCLN_{\left(24;40\right)}=2^3=8\\ \RightarrowƯC_{\left(40;24\right)}=Ư_{\left(8\right)}=\left\{1;2;4;8\right\}\\ b,80=2^4.5\\ 144=2^4.3^2\\ \Rightarrow UCLN_{\left(80;144\right)}=2^4=16\\ \RightarrowƯC_{\left(80;144\right)}=Ư_{\left(16\right)}=\left\{1;2;4;8;16\right\}\\ c,9=3^2\\ 18=2.3^2\\ 72=3^2.2^3\\ \Rightarrow UCLN_{\left(8;18;72\right)}=3^2=9\\ \RightarrowƯC_{\left(9;18;72\right)}=Ư_{\left(9\right)}=\left\{1;3;9\right\}\\ d,25=5^2\\ 55=5.11\\ 75=5^2.3\\ \Rightarrow UCLN_{\left(25;55;75\right)}=5\\ \RightarrowƯC_{\left(25;55;75\right)}=Ư_{\left(5\right)}=\left\{1;5\right\}\)

3:

a: \(40=2^3\cdot5;24=2^3\cdot3\)

=>\(ƯCLN\left(40;24\right)=2^3=8\)

=>\(ƯC\left(40;24\right)=Ư\left(8\right)=\left\{1;-1;2;-2;4;-4;8;-8\right\}\)

b: \(12=2^2\cdot3;52=2^2\cdot13\)

=>\(ƯCLN\left(12;52\right)=2^2=4\)

=>\(ƯC\left(12;52\right)=\left\{1;-1;2;-2;4;-4\right\}\)

c: \(36=2^2\cdot3^2;990=2\cdot3^2\cdot5\cdot11\)

=>\(ƯCLN\left(36;990\right)=3^2\cdot2=18\)

=>\(ƯC\left(36;990\right)=\left\{1;-1;2;-2;3;-3;6;-6;9;-9;18;-18\right\}\)

2:

a: \(12=2^2\cdot3;18=3^2\cdot2\)

=>\(ƯCLN\left(12;18\right)=2\cdot3=6\)

b: \(12=2^2\cdot3;10=2\cdot5\)

=>\(ƯCLN\left(12;10\right)=2\)

c: \(24=2^3\cdot3;48=2^4\cdot3\)

=>\(ƯCLN\left(24;48\right)=2^3\cdot3=24\)

d: \(300=2^2\cdot3\cdot5^2;280=2^3\cdot5\cdot7\)

=>\(ƯCLN\left(300;280\right)=2^2\cdot5=20\)

a) 40 và 24

Ta có: 40 = 2³ . 5

          24 = 2³ . 3

=> ƯCLN(40; 24) = 2³ = 8

=> ƯC(40; 24) \(\in\) Ư(8)

=> ƯC(40; 24) \(\in\) Ư(8) = { 1; 2; 4; 8 }

   Các câu còn lại tương tự nha bạn

ƯCLN(24,40)=8

=>ƯC(24,40)=Ư(8)=(1,2,4,8)

các cau khac tuong tu nhe ban

tìm ƯC(24, 40)

Ta có:

40 = 2³.5

24 = 2³.3

=> ƯCLN(40;24) = 2³ = 8

=> ƯC(40;24) = Ư(8) = {1 ; -1 ; 2 ; -2 ; 4 ; -4 ; 8 ; -8}

Nếu bn chưa học tập hợp Z thì ƯC(40;24) = Ư(8) = {1 ; 2 ; 4 ; 8}

40 = 2³ . 5

24 = 2³ . 3

ƯCLN(40, 24) = 2³ = 8

Ư(8) = {1;2;4;8}

Vậy ƯC(40, 24) = {1;2;4;8}

\(40=2^3.5\)

\(24=2^3.3\)

\(\Rightarrow UwCLN\left(40;24\right)=2^3=8\)

\(Ư\left(8\right)=\left\{1;2;4;8\right\}\)

Vậy :............

\(\text{Ta có : }\hept{\begin{cases}34=2.17\\81=3^4\\55=5.11\end{cases}}\Rightarrow\left(34,81,55\right)=1\)

\(\RightarrowƯC\left(34,81,55\right)=Ư\left(1\right)=\left\{-1;1\right\}\)

Hk tốt

Ta có: 34=2.17

           81=3⁴

           55=5.11

=>ƯCLN(34;81;55)=1

=>ƯC(34;81;55)\(\in\)Ư(1)={1;-1}

Bài 1: 

a: UCLN(12;52)=4

UC(12;52)={1;2;4}

tìm ƯC , thông qua tìm ƯCLN : a) 300 và 280 

mình viết nhầm đề

\(a,ƯC\left(40,24\right)=Ư\left(8\right)=\left\{...\right\}\\ b,ƯC\left(12,52\right)=Ư\left(4\right)=\left\{...\right\}\\ c,ƯC\left(36,990\right)=Ư\left(18\right)=\left\{...\right\}\\ d,ƯC\left(54,36\right)=Ư\left(9\right)=\left\{...\right\}\\ e,ƯC\left(10,20,70\right)=Ư\left(10\right)=\left\{...\right\}\\ f,ƯC\left(25,55,75\right)=Ư\left(5\right)=\left\{...\right\}\\ g,ƯC\left(80,144\right)=Ư\left(16\right)=\left\{...\right\}\\ h,ƯC\left(63,2970\right)=Ư\left(9\right)=\left\{...\right\}\\ i,ƯC\left(65,125\right)=Ư\left(5\right)=\left\{...\right\}\\ j,ƯC\left(9,18,72\right)=Ư\left(9\right)=\left\{...\right\}\\ k,ƯC\left(24,36,60\right)=Ư\left(12\right)=\left\{...\right\}\\ l,ƯC\left(16,42,86\right)=Ư\left(2\right)=\left\{..\right\}\)

a:UC(40;24)=Ư(8)

b: UC(12;52)=Ư(4)

a) ƯCLN (12 ; 18 ; 54) = 6   => ƯC(12 ; 18 ; 54) = Ư (6) = {1 ; 2 ; 3 ; 6 ; -1 ; -2 ; -3 ; -6 }

b) ƯCLN (144 ; 120 ; 170 ) = 2  => ƯC ( 140 ; 120 ; 144 ) = {1 ; 2 ; -1 ; -2}

c) ƯCLN (150 ; 350 ) = 50   => ƯC ( 150 ; 350 ) = {1 ; 2 ; 5 ; 10 ; 25 ; 50 ; -1 ; -2 ; -5 ; -10 ; -25 ; -50}

d) ƯCLN ( 1800 ; 190 ) = 10  => ƯC ( 1800 ; 190) = {1 ; 2 ; 5 ; 10 ; -1 ;-2 ; -5 ; -10}

ƯC(12;18 và 54) = {1;2;3;6}

ƯC(144;120 và 170) = {1;2}

ƯC (150 và 350) = {1;2;5;10}

a)ƯC(12,18,54) = Ư(6) = {1;2;3;6}

b)ƯC(120,144,170)= {1;2}

c)ƯC(190,1800)= {1;2;5;10}