a) x - \(\frac{1}{8}\)= \(\frac{7}{3}\)x \(\frac{21}{4}\)

   x - \(\frac{1}{8}\)= \(\frac{49}{4}\)

             x = \(\frac{49}{4}\)+ \(\frac{1}{8}\)

             x = 98

b) x : \(\frac{3}{2}\) = \(\frac{1}{4}\)

               x = \(\frac{1}{4}\)x \(\frac{3}{2}\)

              x = \(\frac{3}{8}\)

c) \(\frac{103}{10}\) - x = \(\frac{4}{5}\)

                    x = \(\frac{103}{10}\)- \(\frac{4}{5}\)

                    x = \(\frac{19}{5}\)

d) x = 51 x \(\frac{4}{17}\)

    x = \(12\)

Vậy chị kết luận ngắn gọn là:

a)=98

b)=3/8

c)=19/5

d)=12

a) 3+2*x=15

2x=15-3

2x=12

x=12:2

x=6

Vậy x=6

b) 24-x=19

x=24-19

x=5

Vậy x=5

c) 29x-13=45

29x=45+13

29x=58

x=58:29

x=2

Vậy x=2

d) 5x-17=38

5x=38+17

5x=55

x=55:5

x=11

Vậy x=11

e) 50-2(x+1)=20

2(x+1)=50-20

2(x+1)=30

x+1+30/2

x+1=15

x=15-1=14

Vậy x=14

f) 

cho mình hỏi "va"là gì zợ

\(\dfrac{4}{5}\cdot x+\dfrac{1}{3}=1,5\)

\(\Rightarrow\dfrac{4}{5}\cdot x=1,5-\dfrac{1}{3}\)

\(\Rightarrow\dfrac{4}{5}\cdot x=\dfrac{7}{6}\)

\(\Rightarrow x=\dfrac{7}{6}:\dfrac{4}{5}\)

\(\Rightarrow x=\dfrac{35}{24}\)

1) \(|5x-3|=|7-x|\)

\(\Leftrightarrow\orbr{\begin{cases}5x-3=7-x\\5x-3=x-7\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}6x=10\\4x=-4\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=\frac{5}{3}\\x=-1\end{cases}}\)

Vậy...

2) \(2.|3x-1|-3x=7\)

\(\Leftrightarrow2.|3x-1|=7+3x\)

\(\Leftrightarrow\orbr{\begin{cases}2.\left(3x-1\right)=7+3x\\2.\left(3x-1\right)=-7-3x\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}6x-2=7+3x\\6x-2=-7-3x\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}3x=9\\9x=-5\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=3\\x=\frac{-5}{9}\end{cases}}\)

Vậy...

5) \(\text{1,6 - |x + 1,5| = 0}\)

\(|x + 1,5| = 1,6-0\)

\(\text{|x + 1,5| = 1,6}\)

\( |x | = 1,6-1,5\)

\(|x|=0,1\)