\(25\times20\times125\times8-8\times30\times5\times125\\ =125\times500\times8-8\times150\times125\\ =125\times4000-1200\times125\\ =125\times\left(4000-1200\right)\\ =125\times2800\\ =350000\)

4 × 125 × 25 × 8

= (4 × 25) × (125 × 8)

= 100 × 1000

= 100 000

2 × 8 × 50 × 25 × 125

= (2 × 50) × (8 × 125) × 25

= 100 × 1000 × 125

= 12 500 000

2 × 3 × 4 × 5 × 50 × 25

= (2 × 50) × (4 × 25) × (3 × 5)

= 100 × 100 × 15

= 150 000

25 × 20 × 125 × 8 - 8 × 20 × 5 × 125

= 8 × 125 × 20 × (25 - 5)

= 1000 × 20 × 20

= 400 000

- (25 x 4) x (125 x8)=100 x 1000 =100000

- (50 x 2) x (8 x 125) x 25=100 x 1000 x 25 =2500000

- (2 x 50 ) x (4 x 25) x (3 x5)=100 x 100 x 15=150000

- 25 x 20 x125 x 8 - 5

= (20 x 5) x (125 x 8) -25=100 x 1000 -5 =100000 - 5 =99995

4 *125*25*8

=4*25*125*8

=100*1000

=100000

2*8*50*25*125

=2*50*8*125*25

=100*1000*25

=2500000

2*3*4*5*50*25

=2*50*4*25*3*5

=100*100*15

=150000

25*20*125*8-8*20*5*125

=25*4*5*125*8-8*125*20*5

=100*1000*5-1000*100

=500000-100000

=400000

=

a) \(x.125=32250\)

\(x=32250:125\)

\(x=258\)

b) \(39975:x=123\)

\(x=39975:123\)

\(x=325\)

\(x\times125=32250\)

\(\Rightarrow x=258\)

_____

\(39975:x=123\)

\(\Rightarrow x=325\)

a)Xx125=32250

⇒ X=32250:125

⇒ X=258

b) 39975:X=123

⇒ X=39975:123

⇒ X=325

a, 2 x 7,65 x 5

= ( 2 x 5 ) x 7,65

= 10 x 7,65 

= 76,5

b, 25 x 1,9 x 4

= ( 25 x 4 ) x 1,9

= 100 x 1,9 

= 190

c , 6,92 x 8 x 125

= 6,92 x ( 125 x8 )

= 6,92 x 1000

= 6920

d, 15,7 x 8 + 15,7 x2

= 15,7 x ( 8 + 2 )

= 15,7 x 10 

= 157

a,2100   b,190   c,6920   d,157

\(\left(x+5\right)+\left(x+10\right)+...+\left(x+25\right)-125=150\)
\(\Leftrightarrow x+5+x+10+...+x+25-125=150\)
\(\Leftrightarrow5x-50=150\)
\(\Leftrightarrow5x=100\)
\(\Leftrightarrow x=\dfrac{100}{5}=20\)
Vậy \(x=20\)

x = 20

Bài kia mik làm sai r 
\(\left(x+5\right)+\left(x+10\right)+...+\left(x+25\right)-125=150\)
\(\Leftrightarrow x+5+x+10+...+x+25-125=150\)
\(\Leftrightarrow5x-50=150\)
\(\Leftrightarrow5x=200\)
\(\Leftrightarrow x=\dfrac{200}{5}=40\)
Vậy \(x=40\)

\(\frac{120\times999+120}{2\times4\times0,8\times5\times2,5\times125}\)

\(=\frac{120\times1000}{\left(125\times0,8\right)\left(4\times2,5\right)\left(2\times5\right)}\)

\(=\frac{120000}{100\times10\times10}\)

\(=\frac{120000}{10000}\)

\(=\frac{12}{1}=12\)

1. \(\Leftrightarrow\frac{59-x}{41}+1+\frac{57-x}{43}+1+\frac{55-x}{45}+1+\frac{51-x}{49}+1=-5+5\)

 \(\Leftrightarrow\frac{100-x}{41}+\frac{100-x}{43}+\frac{100-x}{45}+\frac{100-x}{47}+\frac{100-x}{49}=0\)

 \(\Leftrightarrow\left(100-x\right)\left(\frac{1}{41}+\frac{1}{43}+\frac{1}{45}+\frac{1}{47}+\frac{1}{49}\right)=0\)

 \(\Leftrightarrow x-100=0\Leftrightarrow x=100\)

2. \(\Leftrightarrow\frac{x-5}{1990}+1+\frac{x-15}{1980}+1+\frac{x-25}{1970}=\frac{x-1990}{5}+1+\frac{x-1980}{15}+1+\frac{x-1970}{25}+1\)

   \(\Leftrightarrow\frac{x-1995}{1990}+\frac{x-1995}{1980}+\frac{x-1995}{1970}=\frac{x-1995}{5}+\frac{x-1995}{15}+\frac{x-1995}{25}\)

   \(\Leftrightarrow\frac{x-1995}{1990}+\frac{x-1995}{1980}+\frac{x-1995}{1970}-\frac{x-1995}{5}-\frac{x-1995}{15}-\frac{x-1995}{25}=0\)

  \(\Leftrightarrow\left(x-1995\right)\left(\frac{1}{1990}+\frac{1}{1980}+\frac{1}{1970}-\frac{1}{5}-\frac{1}{15}-\frac{1}{25}\right)=0\)

  \(\Leftrightarrow x-1995=0\Leftrightarrow x=1995\)

câu 3 hình như sai đề