giai phuong trinh
\(\left(\sqrt{x+5}-\sqrt{x+2}\right)\left(1+\sqrt{x^2+7x+10}\right)=3\)
Những câu hỏi liên quan
giai phuong trinh \(\sqrt{x\left(x-3\right)}-\sqrt{7x-3}=2\sqrt{x^2}\)
giai phuong trinh
\(2\sqrt[3]{\left(x+2\right)^2}-\sqrt[3]{\left(x-2\right)^2}=\sqrt[3]{x^2-4}\)
\(2\sqrt[3]{\left(x+2\right)^2}-\sqrt[3]{\left(x-2\right)^2}=\sqrt[3]{x^2-4}\)
\(\Leftrightarrow\sqrt[3]{\left(x-2\right)^2}=\sqrt[3]{x^2-4}\)
\(\Rightarrow\left(x-2\right)^2=x^2-4\)
\(\Leftrightarrow x^2-4x+4-x^2+4=0\)
\(\Leftrightarrow-4x+8=0\)
\(\Leftrightarrow x=2\)
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Đặt \(\sqrt[3]{x+2}=a;\sqrt[3]{x-2}=b;\) ta có:
\(2a^2-b^2=ab\) ⇔ \(2a^2-ab-b^2=0\)
\(\Leftrightarrow2a^2+ab-2ab-b^2=0\)
⇔ \(\left(2a+b\right)\left(a-b\right)=0\)
⇔ \(\left[{}\begin{matrix}2\sqrt[3]{x+2}=-\sqrt[3]{x-2}\\\sqrt[3]{x-2}=\sqrt[3]{x+2}\end{matrix}\right.\)⇔ \(x=-\frac{14}{9}\)
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Giai phuong trinh : \(\left(x+5\right)\sqrt{\left(x+1\right)+1}=\sqrt[3]{\left(3x+4\right)}\)
lớp 7 sao mà đã học căn thức ak bạn.có lớp 8 thì đc
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Giai phuong trinh
\(\sqrt{x.\left(x-1\right)}+\sqrt{x\left(x+2\right)}=2x\)
x=0
nhanh nhất có thể
X=0
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Giai phuong trinh va he phuong trinh:
a) \(\sqrt{x^2+6}=x-2\sqrt{x^2-1}\)
b) \(x^2+3x+1=\left(x+3\right).\sqrt{x^2+1}\)
c) \(\left\{{}\begin{matrix}x^2+y^2=11\\x+xy+y=3+4\sqrt{2}\end{matrix}\right.\)
Giai phương trình:\(\left(\sqrt{x+5}-\sqrt{x+2}\right)\left(\sqrt{x^2+7x+10}+1\right)=3\)
\(\left(\sqrt{x+5}-\sqrt{x+2}\right)\left(\sqrt{x^2+7x+10}+1\right)=3\)
\(\Leftrightarrow\left(\sqrt{x+5}-\sqrt{x+2}\right)\left(\sqrt{\left(x+5\right)\left(x+2\right)}+1\right)=3\)
Đặt \(\hept{\begin{cases}\sqrt{x+5}=a\left(a\ge0\right)\\\sqrt{x+2}=b\left(b\ge0\right)\end{cases}}\)
\(\Rightarrow\hept{\begin{cases}a^2-b^2=3\\\left(a-b\right)\left(ab+1\right)=3\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}a^2-b^2=3\\\left(a-b\right)\left(ab+1-a-b\right)=0\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}a^2-b^2=3\\\left(a-b\right)\left(a-1\right)\left(b-1\right)=0\end{cases}}\)
Với a = b thì
\(\sqrt{x+5}=\sqrt{x+2}\Leftrightarrow0x=3\left(l\right)\)
Với a = 1 thì
\(\sqrt{x+5}=1\Leftrightarrow x=-4\left(l\right)\)
Với b = 1 thì
\(\sqrt{x+2}=1\Leftrightarrow x=-1\)
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Giai phuong trinh giup minh 3 cau nay voi
a,\(3x\left(2-\sqrt{4}\right)=3\left(\sqrt{4}x+1\right)\)
b,\(\left(5-x\right).\left(\sqrt{3}+x\right)-5=0.\)
c,\(\left(x^2-2x\right)+\left(-4+8x\right)=0.\)
Giai cac phuong trinh vo ti sau
1. \(\sqrt{\sqrt{3}-x}=x\sqrt{\sqrt{3}+x}\)
2. \(\left(\sqrt{1+x}-1\right)\left(\sqrt{1-x}+1\right)=2x\)
3. \(x=\left(2018+\sqrt{x}\right)\left(1-\sqrt{1-\sqrt{x}}\right)^2\)
giup mk nha
Giai phuong trinh : \(2\left(x^2+2\right)=5\sqrt{x^3+1}\)
Đặt \(\hept{\begin{cases}\sqrt{x+1}=a\\\sqrt{x^2-x+1}=b\end{cases}}\)
\(\Rightarrow2\left(a^2+b^2\right)=5ab\)
\(\Leftrightarrow\left(b-2a\right)\left(2b-a\right)=0\)
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