27/82<1/3 ; 26/75>1/3

27/82 < 26/75

27/82<1/3 ; 26/75>1/3

Ta có 26/75>25/75=1/3 mà 27/82<1/3

=>27/82<26/75

16/9 < 24/13

27/82 < 26/75

(k) đúng cho mình

16/9<24/13

27/82>26/75

16/9<24/13

27/82>26/75

a) Ta quy đồng mẫu số:
24/3=48/9
vì 16<48 nên 16/9<48/9
vậy 16/9<24/3
b) Ta có :
27/82<1/3
26/75>1/3
vậy 27/82<26/75

a) Ta có:

\(\dfrac{16}{9}\)=\(\dfrac{48}{27}\)                 \(\dfrac{24}{13}=\dfrac{48}{26}\)

Vì 27>26

➝\(\dfrac{48}{27}>\dfrac{48}{26}hay\dfrac{16}{9}>\dfrac{24}{13}\)

So sánh:

a) 16/9 và 24/13 

 Ta có \(\dfrac{16}{9}=\dfrac{208}{117}\) và \(\dfrac{24}{13}=\) \(\dfrac{216}{117}\)

\(\Rightarrow\dfrac{216}{117}>\dfrac{208}{117}\Rightarrow\dfrac{24}{13}>\dfrac{16}{9}\)

b) 27/82 và 26/75

Ta có \(\dfrac{27}{82}\approx0,33\) và \(\dfrac{26}{75}\approx0,35\)

\(\Rightarrow9,35>0,33\Rightarrow\dfrac{26}{75}>\dfrac{27}{82}\)

a) Ta có: \(\dfrac{16}{9}=\dfrac{16\cdot13}{9\cdot13}=\dfrac{208}{117}\)

\(\dfrac{24}{13}=\dfrac{24\cdot9}{13\cdot9}=\dfrac{216}{117}\)

mà \(\dfrac{208}{117}< \dfrac{216}{117}\)

nên \(\dfrac{16}{9}< \dfrac{24}{13}\)

giúp mk với

so sanh -49/78

Trả lời:

\(a.\frac{27}{82}< \frac{26}{75}\)

\(b.\frac{-49}{78}< \frac{64}{-95}\)

***

\(\dfrac{27}{82}< \dfrac{27}{81}=\dfrac{1}{3}=\dfrac{25}{75}< \dfrac{26}{75}\)

Vậy \(\dfrac{27}{82}< \dfrac{26}{75}\)

\(a,\frac{2}{3}>\frac{1}{4}\)

\(b,\frac{7}{10}< \frac{7}{8}\)

\(c,\frac{6}{7}>\frac{3}{5}\)

\(d,\frac{14}{21}< \frac{60}{72}\)

\(e,\frac{16}{9}< \frac{24}{13}\)

\(g,\frac{27}{82}< \frac{26}{75}\)

a 2/3 > 1/4

b 7/10 < 7/8

c6/7 > 3/5

d14/21 < 60/72

e16/9 < 24/13

g27/82<26/75