a, / 2 + x / + / x - 7 / = 3
b, / 13 -x / + / 6 - x / = 7
c, / 8 + x / + / x - 5 / = 17
d, / 16 - x / + / 7 + x / = 22
f, / 8 + x / + / x - 8 / = 10
Tính bằng cách thuận tiện nhất:
a) 16, 2 x 3, 7 + 5, 7 x 16, 2 - 7, 8 x 4, 8 - 4, 6 x 7, 8 : 11, 2 + 12, 3 + 13, 4 - 12, 6 - 11, 5 - 10, 4
a, 3/5 + X = 4/3
b, X + 5/6 =1/7
c, X x 3/8 = 3/4
d, 4/5 x X = 3/7
a) \(\dfrac{3}{5}+x=\dfrac{4}{3}\)
\(\Leftrightarrow x=\dfrac{4}{3}-\dfrac{3}{5}\)
\(\Leftrightarrow x=\dfrac{20}{15}-\dfrac{9}{15}\)
\(\Leftrightarrow x=\dfrac{11}{15}\)
b) \(x+\dfrac{5}{6}=\dfrac{1}{7}\)
\(\Leftrightarrow x=\dfrac{1}{7}-\dfrac{5}{6}\)
\(\Leftrightarrow x=\dfrac{6}{42}-\dfrac{35}{42}\)
\(\Leftrightarrow x=-\dfrac{29}{42}\)
c) \(x\times\dfrac{3}{8}=\dfrac{3}{4}\)
\(\Leftrightarrow x=\dfrac{3}{4}:\dfrac{3}{8}\)
\(\Leftrightarrow x=\dfrac{3}{4}\times\dfrac{8}{3}\)
\(\Leftrightarrow x=2\)
d) \(\dfrac{4}{5}\times x=\dfrac{3}{7}\)
\(\Leftrightarrow x=\dfrac{3}{7}:\dfrac{4}{5}\)
\(\Leftrightarrow x=\dfrac{3}{7}\times\dfrac{5}{4}\)
\(\Leftrightarrow x=\dfrac{15}{28}\)
a, \(\dfrac{3}{5}+x=\dfrac{4}{3}\Leftrightarrow x=\dfrac{4}{3}-\dfrac{3}{5}=\dfrac{20-9}{15}=\dfrac{11}{15}\)
b, \(x+\dfrac{5}{6}=\dfrac{1}{7}\Leftrightarrow x=\dfrac{1}{7}-\dfrac{5}{6}=\dfrac{6-35}{42}=\dfrac{-29}{42}\)
c, \(\dfrac{3x}{8}=\dfrac{3}{4}\Leftrightarrow\dfrac{3x}{8}=\dfrac{6}{8}\Rightarrow3x=6\Leftrightarrow x=2\)
d, \(\dfrac{4x}{5}=\dfrac{3}{7}\Leftrightarrow\dfrac{28x}{35}=\dfrac{15}{35}\Rightarrow x=\dfrac{15}{28}\)
a, \(\dfrac{3}{5}\) + \(X\) = \(\dfrac{4}{3}\)
\(X\) = \(\dfrac{4}{3}\) - \(\dfrac{3}{5}\)
\(X\) = \(\dfrac{11}{15}\)
b, \(X\) + \(\dfrac{5}{6}\) = \(\dfrac{1}{7}\)
\(X\) = \(\dfrac{1}{7}\) - \(\dfrac{5}{6}\)
\(X\) = -\(\dfrac{29}{42}\)
c, \(X\) x \(\dfrac{3}{8}\) = \(\dfrac{3}{4}\)
\(X\) = \(\dfrac{3}{4}\) : \(\dfrac{3}{8}\)
\(X\) = 2
d, \(\dfrac{4}{5}\) x \(X\) = \(\dfrac{3}{7}\)
\(X\) = \(\dfrac{3}{7}\) : \(\dfrac{4}{5}\)
\(X\) = \(\dfrac{15}{28}\)
#Yu
Tính:
a) 2^5 x 13^12 x 7^8 : 27 x 13^10 x 7^9
b) 2^n x 11 x 3 : 6^n x 3
c) 5^5 x 7 x 9^5 : 15^10
d) 7 x 8^10 x 27^9 - 8 x 9^13 x 2^27 : 7 x 6^26 x 2^2 - 2^4 x 8^3 x 27^9
e) 2^2^1^2015
f) 2015^0^2015^0^2015
Tính:
a) 2^5 x 13^12 x 7^8 : 2^7 x 13^10 x 7^9
b) 2^n x 11 x 3 : 6^n x 3
c) 5^5 x 7 x 9^5 : 15^10
d) 7 x 8^10 x 27^9 - 8 x 9^13 x 2^27 : 7 x 6^26 x 2^2 - 2^4 x 8^3 x 27^9
e) 2^2^1^2015
f) 2015^0^2015^0^2015
1/ 10(X-7)-8(X+5)=6(-5)+24
2/ 8(X-|-7|)-6(X-2)=|-8|.6-50
3/ 2(4X-8)-7(3+X)=|-4|(3-2)
4/ 12(X-4)=6(x-2)-16(X+3)=7|-4|
5/ 4(X-5)-7(5-X)+10(5-X)=-3
bn nào giải giúp mik vs nha:)))
1/ 10(X-7)-8(X+5)=6(-5)+24
10x - 70 - 8x - 40 = -30 +24
2x - 110 = -6
2x = 104
x=52
2/ 8(X-|-7|)-6(X-2)=|-8|.6-50
8(x - 7) - 6(x-2) = 8.6 - 50
8x - 56 - 6x +12 =48 -50
2x - 44 = -2
2x = 42
x=21
3/ 2(4X-8)-7(3+X)=|-4|(3-2)
8x-16 - 21 - 7x = 4.1
x-37=4
x=41
4/ 12(X-4)=6(x-2)-16(X+3)=7|-4|
12x - 48 = 6x - 12 - 16x -48 =7.4
12x - 48 = 28
12x=76
x=19/3
5/ 4(X-5)-7(5-X)+10(5-X)=-3
4x - 20 -35 +7x + 50 -10x = -3
x - 5 = -3
x = -2
Chúc bạn học tốt!
Phân tích các đa thức sau thành nhân tử.
1) a^2+ab+2b-4 2) x^3-x 3) x^2-6x+8 4) ab+b^2-3a-3b 5) x^3-4x^2-8x+8
6)9x^2+6x-8 7)x^2-y^2-4x+4 8)5x^3-10x^2+5x 9) 3x^2-8x+4 10) 4x^2-4x-3
11) x^2-7x+12 12)x^2-5x-14 13) 3x^2-7x+2 14) a.(x^2+1)-x.(a^2-1) 15) x^4+4
16) (x+2).(x+3).(x+4).(x+5)-24 17) (a+1).(a+3).(a+5).(a+7)+15
Tính
a, -(-5)-(+7)+(+3)+(-8)
b, -(-15)-|-10|+|-9|-|5|
c, 14-(-13)-(17)+(-12)
d, -|-14| + |-10| - (-12) + (-8)
e, -(-11) + (-15) + (13) - 21
Bài 2 tìm x
1, -x + 20 = - (-15) - (8) + 13
2, -(-10) + x = -13 + (-9) + (-6)
3, 8-(-12) + 10 = - (-14) - x
4. - (+12) + (-x) - (-3) = 5 - (-7)
5. 14 - x + (-10) = - (-9) + (+15)
6. 12 - (-17) + (-3) = -5 + x
7. X - (-19) - (+32) = 14 - (+16)
8. X - |-15| - |7| = - (-9) + |-5|
9. 15 - x + 17 = 13 - (-21)
10. - |-5| - (-x) +4 = 3 - (-25)
Mọi NGƯỜI GIẢI GIÚP MÌNH VỚI MK CẦN GẤP, MỌI NGƯỜI GHI RÕ CÁCH LÀM RA NHÉ! CẢM ƠN MỌI NGƯỜI
Bạn ơi bạn làm đc bao nhiêu thì làm phụ mình nhé
bài1
a,
5 - 7 + 3 +(-8)
= -2 + 3 + ( - 8)
= 1 + (-8)= -7
a; - (-5) - (+7) + (+3) + (-8)
= 5 - 7 + 3 - 8
= (5 + 3 - 8) - 7
= (8 - 8) - 7
= 0 - 7
= - 7
Bài 46:
11, - 4|x-2| = -8
12, 5|x+2| = -10(-2)
13, 6|x-2| = 18: (- 3)
14, -7|x+4| = 21 : (-3)
15, 4|x+1| = 8(-2) - 8(-5)
16, 3|x+5| = -9
17, -8|x-3| = 24 - 16: 2
18, -3|x+6| = 6.2 -9
19, 5-|x+7| = 4
20, 12-|x+8| = 10
Giúp mk nha. Mk càn ngay đó
Bài 46:
11: Ta có: \(-4\left|x-2\right|=-8\)
\(\Leftrightarrow\left|x-2\right|=2\)
\(\Leftrightarrow\left[{}\begin{matrix}x-2=2\\x-2=-2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=4\\x=0\end{matrix}\right.\)
Vậy: x∈{0;4}
12: Ta có: \(5\left|x+2\right|=-10\cdot\left(-2\right)\)
\(\Leftrightarrow5\left|x+2\right|=20\)
\(\Leftrightarrow\left|x+2\right|=4\)
\(\Leftrightarrow\left[{}\begin{matrix}x+2=4\\x+2=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-6\end{matrix}\right.\)
Vậy: x∈{-6;2}
13: Ta có: \(6\left|x-2\right|=18:\left(-3\right)\)
\(\Leftrightarrow6\left|x-2\right|=-6\)(1)
Ta có: \(\left|x-2\right|\ge0\forall x\)
\(\Rightarrow6\left|x-2\right|\ge0\forall x\)(2)
Ta có: -6<0(3)
Từ (1), (2) và (3) suy ra x∈∅
Vậy: x∈∅
14: Ta có:\(-7\left|x+4\right|=21:\left(-3\right)\)
\(\Leftrightarrow-7\left|x+4\right|=-7\)
\(\Leftrightarrow\left|x+4\right|=1\)
\(\Leftrightarrow\left[{}\begin{matrix}x+4=1\\x+4=-1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-3\\x=-5\end{matrix}\right.\)
Vậy: x∈{-5;-3}
15: Ta có: \(4\left|x+1\right|=8\left(-2\right)-8\left(-5\right)\)
\(\Leftrightarrow4\left|x+1\right|=-16-\left(-40\right)\)
\(\Leftrightarrow4\left|x+1\right|=24\)
\(\Leftrightarrow\left|x+1\right|=6\)
\(\Leftrightarrow\left[{}\begin{matrix}x+1=6\\x+1=-6\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=5\\x=-7\end{matrix}\right.\)
Vậy: x∈{-7;5}
16: Ta có: \(3\left|x+5\right|=-9\)(4)
Ta có: |x+5|≥0∀x
⇒3|x+5|≥0∀x(5)
Ta có: -9<0(6)
Từ (4), (5) và (6) suy ra x∈∅
Vậy: x∈∅
17: Ta có: \(-8\left|x-3\right|=24-16:2\)
\(\Leftrightarrow-8\left|x-3\right|=16\)
\(\Leftrightarrow\left|x-3\right|=-2\)
mà |x-3|≥0>-2∀x
nên x∈∅
Vậy: x∈∅
18: Ta có: \(-3\left|x+6\right|=6\cdot2-9\)
\(\Leftrightarrow-3\left|x+6\right|=3\)
\(\Leftrightarrow\left|x+6\right|=-1\)
mà |x+6|≥0>-1∀x
nên x∈∅
Vậy: x∈∅
19: Ta có: \(5-\left|x+7\right|=4\)
\(\Leftrightarrow\left|x+7\right|=1\)
\(\Leftrightarrow\left[{}\begin{matrix}x+7=-1\\x+7=1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-8\\x=-6\end{matrix}\right.\)
Vậy: x∈{-8;-6}
20: Ta có: \(12-\left|x+8\right|=10\)
\(\Leftrightarrow\left|x+8\right|=2\)
\(\Leftrightarrow\left[{}\begin{matrix}x+8=2\\x+8=-2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-6\\x=-10\end{matrix}\right.\)
Vậy: x∈{-10;-6}
x = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 .
x = 2 + 4 + 6 + 8 + 10 + 12 + 14 + 16 + 18 + 20 .
x = 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 .
X = ( 1+10 ) * 10 / 2 = 11 * 10 / 2 = 110 / 2 = 55
X= (2+20) * 10 /2 = 110
X= (1+19)*10/2= 100
1+2+3+4+5+6+7+8+9+10= (10+1)X10 : 2 = 55
2+4+6+8+10+12+14+16+18+20 = (20+2)x10 : 2 = 110
1+3+5+7+9+11+13+15+17+19 = (19+1) x 10 : 2 = 100
x=55
x=110
x=100