\(\frac{2017_{ }\times2018+2}{2018\times2018-2016}\)
Giải hô mình
Những câu hỏi liên quan
a) frac{-3}{100}vàfrac{2}{3} b)frac{267}{-268}vàfrac{-1347}{1343}c)frac{2017times2018-1}{2017times2018}vàfrac{2018times2019-1}{2018times2019}d)frac{2017times2018}{2017times2018+1}vàfrac{2018times2019}{2018times2019+1}
Đọc tiếp
a) \(\frac{-3}{100}\)và\(\frac{2}{3}\) b)\(\frac{267}{-268}\)và\(\frac{-1347}{1343}\)c)\(\frac{2017\times2018-1}{2017\times2018}\)và\(\frac{2018\times2019-1}{2018\times2019}\)d)\(\frac{2017\times2018}{2017\times2018+1}\)và\(\frac{2018\times2019}{2018\times2019+1}\)
a) Ta có : \(\frac{-3}{100}< 0< \frac{2}{3}\)
\(\Rightarrow\frac{-3}{100}< \frac{2}{3}\)
b) Ta có : \(\frac{267}{268}< 1< \frac{1347}{1343}\)
\(\Rightarrow\frac{267}{268}< \frac{1347}{1343}\)
\(\Rightarrow\frac{267}{-268}< \frac{-1347}{1343}\)
c) Ta có : \(\frac{2017.2018-1}{2017.2018}=\frac{2017.2018}{2017.2018}-\frac{1}{2017.2018}=1-\frac{1}{2017.2018}\)
\(\frac{2018.2019-1}{2018.2019}=\frac{2018.2019}{2018.2019}-\frac{1}{2018.2019}=1-\frac{1}{2018.2019}\)
mà \(2017.2018< 2018.2019\)
\(\Rightarrow\frac{1}{2017.2018}>\frac{1}{2018.2019}\)
\(\Rightarrow1-\frac{1}{2017.2018}< 1-\frac{1}{2018.2019}\)
\(\Rightarrow\frac{2017.2018-1}{2017.2018}< \frac{2018.2019-1}{2018.2019}\)
d) Ta có : \(\frac{2017.2018}{2017.2018+1}=\frac{2017.2018+1}{2017.2018+1}-\frac{1}{2017.2018+1}=1-\frac{1}{2017.2018+1}\)
\(\frac{2018.2019}{2018.2019+1}=\frac{2018.2019+1}{2018.2019+1}-\frac{1}{2018.2019+1}=1-\frac{1}{2018.2019+1}\)
mà \(2017.2018+1< 2018.2019+1\)
\(\Rightarrow\frac{1}{2017.2018+1}>\frac{1}{2018.2019+1}\)
\(\Rightarrow1-\frac{1}{2017.2018+1}< 1-\frac{1}{2018.2019+1}\)
\(\Rightarrow\frac{2017.2018}{2017.2018+1}< \frac{2018.2019}{2018.2019+1}\)
So sánh: a)frac{-3}{100}và frac{2}{3} b)frac{267}{-268}vàfrac{-1347}{1343} c) frac{2017times2018-1}{2017times2018}vàfrac{2018times2019-1}{2018times2019} e)frac{2017times2018}{2017times2018+1}vàfrac{2018times2019}{2018times2019+1} Gải cách rút gọn cám ơn ạ
Đọc tiếp
So sánh: a)\(\frac{-3}{100}\)và \(\frac{2}{3}\) b)\(\frac{267}{-268}\)và\(\frac{-1347}{1343}\) c) \(\frac{2017\times2018-1}{2017\times2018}\)và\(\frac{2018\times2019-1}{2018\times2019}\) e)\(\frac{2017\times2018}{2017\times2018+1}\)và\(\frac{2018\times2019}{2018\times2019+1}\) Gải cách rút gọn cám ơn ạ
Tính nhanh : \(\frac{2018\times2017-1}{2016\times2018+2017}\)
\(\frac{2018\times2017-1}{2016\times2018+2017}\)
\(=\frac{2018\times\left(2016+1\right)-1}{2016\times2018+2017}\)
\(=\frac{2018\times2016+2018-1}{2016\times2018+2017}\)
\(=\frac{2018\times2016+2017}{2016\times2018+2017}\)
\(=1\)
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Rút gọn A=\(\frac{2014\times2018+2015}{2016^2+2011}\)
25 tháng 2 2022 lúc 20:30
So sánh:\(2017\times2018\times2019\)với\(2018^3\)
Đặt 2018=a
\(VT=a\left(a-1\right)\left(a+1\right)=a\left(a^2-1\right)=a^3-a< a^3\)
Do đó: VT<VP
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so sán a và b biết a=\(\frac{2017\times2018-1}{2017\times2018}\)và b =\(\frac{2019\times2020-1}{2019\times2020}\)
\(Ta\)có :\(a\)=\(\frac{2017\cdot2018-1}{2017.2018}\)=\(\frac{2017.2018}{2017.2018}\)-\(\frac{1}{2017.2018}\)=1-\(\frac{1}{2017.2018}\)
\(b\)=\(\frac{2019.2020-1}{2019.2020}\)=\(\frac{2019.2020}{2019.2020}\)-\(\frac{1}{2019.2020}\)=1-\(\frac{1}{2019.2020}\)
Vì \(\frac{1}{2018.2019}\)> \(\frac{1}{2019.2020}\)nên \(a\)< \(b\)(sử dụng phần bù)
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=\(\left(1+\frac{1}{1\times3}\right)\left(1+\frac{1}{2\times4}\right)\left(1+\frac{1}{3\times5}\right)...\left(1+\frac{1}{2016\times2018}\right)\)
Ai giúp với
= 1.3+1/1.3 . 2.4+1/2.4 . ....... . 2016.2018+1/2016.2018
= 2^2/1.3 . 3^2/2.4 . ....... . 2017^2/2016.2018
= 2.3. ...... . 2017/1.2. ..... . 2016 . 2.3. ..... . 2017/3.4. ...... . 2018
= 2017 . 2/2018
= 2017/1009
Tk mk nha
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Tính luôn :
= 4/3 . 9/8 . 16/15 .. . 4068289/2016 . 2018
= 4/3 . 9/8 . 16/15 . .. 2017 x 2017 / 2016. 2018
= 4 . 9 . 16 ... 2017 . 2017 / 3 . 8 . 15 . ...2016 . 2018
= 2 . 2 . 3 . 3 . 4 . 4 ... 2017 . 2017 / 3 . 2 . 4 . 3 . 5 ...2016 . 2018
= ( 2 . 3 . 4 ... 2017 ) . ( 2 . 3 . 4 ... 2017 ) / ( 3 . 4 . 5 ... 2016 ) . ( 2 . 3 . 4 . 5 ...2018 )
= 2 . 2017 / 2018
= 2017 / 1009
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Tính nhanh
\(2018\times2018-2019\times2017\)
\(2018\times2018-2019\times2017\)
\(=2018\times\left(2017+1\right)-\left(2018+1\right)\times2017\)
\(=2018\times2017+2018-2018\times2017-2017\)
\(=2018\times2017-2018\times2017+2018-2017\)
\(=2018-2017\)
\(=1\)
~~~~~~~~~~~Hok tốt~~~~~~~~~~~
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Tính gía trị của biểu thức
\(\frac{\left(2015^2\times2025+31\times2016-1\right)\times\left(2015\times2020+4\right)}{2016^2\times2017\times2018\times2019\times2020}\)