x+(x+1)+(x+2)+...+(x+30)=1240
=> (x+x+...+x) + (1+2+3...+30) = 1240
=> 31x + 465 = 1240

=> 31x             = 1240 - 465 = 775
=> x                 = 775 : 31
=> x                  = 25

= ( x+x+x+x+x+...+x ) + ( 1+2+3+..+30 ) =1240

=> 31x + 465 = 1240

=> 31x = 775

=> x = 25

x + ( x + 1 ) + ( x + 2 ) + ....... + ( x +30 ) = 1240

( x + x + x + ...... + x ) + ( 1 + 2 + ...... + 30) = 1240

31x + 465 = 1240

31x           = 1240 - 465

31x           = 775

x               = 775 : 31

x               = 25

Vậy x = 25

# HOK TỐT #

a) https://olm.vn/hoi-dap/question/1286785.html

b) 

SSH là :

( x - 1 ) : 1 + 1 = x

Tổng là :

( x + 1 ) . x : 2 = 210

x ( x + 1 ) = 420

mà x và x + 1 là 2 số liên tiếp => 420 = 20 x 21 => x = 20

Vậy,............

\(a,\left(19x+2.5^2\right):14=\left(13-8\right)^2-4^2\)

\(\Leftrightarrow\left(19x+50\right):14=5^2-4^2\)

\(\Leftrightarrow\left(19x+50\right):14=9\)

\(\Leftrightarrow19x+50=126\)

\(\Leftrightarrow19x=76\Leftrightarrow x=4\)

b) x + ( x + 1 ) + ( x + 2 ) + ... + ( x + 30 ) = 1240

x + x + 1 + x + 2 + ... + x + 30 = 1240

( x + x + ... + x ) + ( 1 + 2 + ... + 30 ) = 1240

Số số hạng là : ( 30 - 1 ) : 1 + 1 = 30 ( số )

Tổng là : ( 30 + 1 ) . 30 : 2 = 465

=> 31x + 465 = 1240

=> 31x = 775

=> x = 25

Vậy........

c) 11 - ( -53 + x ) = 97

11 + 53 - x = 97

64 - x = 97

x = 64 - 97

x = -33

a, (19x+2.5²) : 14 = (13-8)² - 4²

(19x + 2.25) : 14 = 5² - 4²

(19x + 50) : 14 = 25 - 16

(19x + 50) : 14 = 9

19 x + 50 = 9.14

19x + 50 = 126 

19x = 126 - 50

19x = 76

x = 76 : 19

x = 4

vậy____

b) x + (x + 1) + (x + 2) + (x + 3)+.....+(x+30) = 1240

(x+x+x+...+x) + (1+2+3+...+30) = 1240

31x + 465 = 1240

31x = 1240 - 465

31x = 775

x = 775 : 31

x = 25

vậy____

c) |x + 7| = 20 + 5.(-3)

|x + 7| = 20 + (-15)

|x + 7| = 5

\(\Rightarrow\orbr{\begin{cases}x+7=5\\x+7=-5\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=5-7\\x=-5-7\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=-2\\x=-12\end{cases}}\)

vậy_____

a) \(\left(19x+2\cdot5^2\right):14=\left(13-8\right)^2-4^2\)

\(\Leftrightarrow\left(19x+2\cdot25\right):14=5^2-4^2\)

\(\Leftrightarrow19x+50=\left(25-16\right)\cdot14\)

\(\Leftrightarrow19x+50=9\cdot14\)

\(\Leftrightarrow19x+50=126-50\)

\(\Leftrightarrow19x=76\)

\(\Leftrightarrow x=76:19\)

\(\Leftrightarrow x=4\)

b) \(x+\left(x+1\right)+\left(x+2\right)+...+\left(x+30\right)=1240\)

\(\Leftrightarrow\left(x+x+x+x...+x\right)+\left(1+2+3+...+30\right)=1240\)

\(\Leftrightarrow31x+\frac{\left[\left(30-1\right):1+1\right]\cdot\left(30+1\right)}{2}=1240\)

\(\Leftrightarrow31x+465=1240\)

\(\Leftrightarrow31x=775\)

\(\Leftrightarrow x=25\)

c)\(11-\left(-53+x\right)=97\)

\(\Leftrightarrow-53+x=-86\)

\(\Leftrightarrow x=-33\)

d) \(-\left(x+84\right)+213=-16\)

\(\Leftrightarrow-\left(x+84\right)=-229\)

\(\Leftrightarrow x+84=229\)

\(\Leftrightarrow x=145\)

a: Ta có: \(\left(5x+1\right)^2-\left(5x-3\right)\left(5x+3\right)=30\)

\(\Leftrightarrow25x^2+10x+1-25x^2+9=30\)

\(\Leftrightarrow10x=20\)

hay x=2

b: Ta có: \(\left(x-1\right)\left(x^2+x+1\right)-x\left(x+2\right)\left(x-2\right)=5\)

\(\Leftrightarrow x^3-1-x^3+4x=5\)

\(\Leftrightarrow4x=6\)

hay \(x=\dfrac{3}{2}\)

\(a,\left(x+2\right)^2-9=0\\ \Leftrightarrow\left(x+2-3\right)\left(x+2+3\right)=0\\ \Leftrightarrow\left(x-1\right)\left(x+5\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=1\\x=-5\end{matrix}\right.\\ Vậy\dfrac{ }{ }S=\left\{1;-5\right\}\)

\(b,x^2-2x+1=25\\ \Leftrightarrow\left(x-1\right)^2=25\\ \Leftrightarrow\left(x-1\right)^2-25=0\\ \Leftrightarrow\left(x-1-5\right)\left(x-1+5\right)=0\\ \Leftrightarrow\left(x-6\right)\left(x+4\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=6\\x=-4\end{matrix}\right.\\ Vậy\dfrac{ }{ }S=\left\{6;-4\right\}\)

\(c,\left(5x+1\right)^2-\left(5x-3\right)\left(5x+3\right)=30\\ \Leftrightarrow25x^2+10x+1-25x^2+9=30\\ \Leftrightarrow25x^2+10x-25x^2=30-1-9\\ \Leftrightarrow10x=20\\ \Leftrightarrow x=2\\ Vậy\dfrac{ }{ }S=\left\{2\right\}\)

\(d,\left(x-1\right)\left(x^2+x+1\right)+x\left(x+2\right)\left(2-x\right)=5\\ \Leftrightarrow x^3-1-x\left(x^2-4\right)=5\\ \Leftrightarrow x^3-1-x^3+4x=5\\ \Leftrightarrow x^3-x^3+4x=5+1\\ \Leftrightarrow4x=6\\ \Leftrightarrow x=\dfrac{3}{2}\\ Vậy\dfrac{ }{ }S=\left\{\dfrac{3}{2}\right\}\)

a: =>(x+2-3)(x+2+3)=0

=>(x-1)(x+5)=0

=>x=1 hoặc x=-5

b: =>(x-1)^2=25

=>x-1=5 hoặc x-1=-5

=>x=-4 hoặc x=6

c: =>25x^2+10x+1-25x^2+9=30

=>10x+10=30

=>x+1=3

=>x=2

d: =>x^3-1-x(x^2-4)=5

=>x^3-1-x^3+4x=5

=>4x=6

=>x=3/2