\(\frac{1212}{3030}=\frac{2}{5}\)

\(\frac{32032}{48048}=\frac{2}{3}\)

\(\frac{456456}{234234}=\frac{76}{39}\)

\(\frac{1339}{1442}=\frac{13}{14}\)

#Châu's ngốc

1) Ta có :  \(\frac{49}{28}=\frac{49:7}{28:7}=\frac{7}{4}\)

             \(\frac{85}{51}=\frac{85:17}{51:17}=\frac{5}{3}\)

             \(\frac{64}{96}=\frac{64:32}{96:32}=\frac{2}{3}\)

             \(\frac{1212}{3030}=\frac{1212:606}{3030:606}=\frac{2}{5}\)

             \(\frac{32032}{48048}=\frac{32032:16016}{48048:16016}=\frac{2}{3}\)

             \(\frac{1339}{1442}=\frac{1339:103}{1442:103}=\frac{13}{14}\)    

Bài 1 :

49/28 =7/4    85/51=5/3   64/96=2/3     1212/3030=2/5     32032/48048=2/3   1339/1442=13/14

49/28=7/4

85/51=5/3

64/96=2/3

1212/3030=2/5

32032/48048=2/3

1339/1442=13/14

mk chắc chắn đúng 100% nên bạn k cho mk nha

chúc bạn học tốt

\(\dfrac{1339}{1442}=\dfrac{1339:103}{1442:103}=\dfrac{13}{14}\)

\(\dfrac{1212}{3030}=\dfrac{1212:606}{3030:606}=\dfrac{2}{5}\)

A=\(\frac{7}{4}.\left(\frac{3333}{1212}+\frac{3333}{2020}+\frac{3333}{3030}+\frac{3333}{4242}\right)\) 

A=\(\frac{7}{4}.\left[33.\left(\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}\right)\right]\) 

A=\(\frac{7}{4}.\left[33.\left(\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}\right)\right]\)

A=\(\frac{7}{4}.\left[33.\left(\frac{1}{3-4}+\frac{1}{4-5}+\frac{1}{5-6}+\frac{1}{6-7}\right)\right]\)

A=\(\frac{7}{4}.\left[33.\left(\frac{1}{3}-\frac{1}{7}\right)\right]\) 

A=\(\frac{7}{4}.\frac{44}{7}\)

A=11

Like cho mình nha bài này viết mỏi tay lắm

\(D=\frac{202202}{1212}+\frac{202202}{2020}+\frac{202202}{3030}+\frac{202202}{4242}+\frac{202202}{5656}\)

\(D=\frac{2002.101}{101.12}+\frac{2002.101}{20.101}+\frac{2002.101}{30.101}+\frac{2002.101}{42.101}+\frac{2002.101}{56.101}\)

\(D=\frac{2002}{12}+\frac{2002}{20}+\frac{2002}{30}+\frac{2002}{42}+\frac{2002}{56}\)

\(D=\frac{1001}{6}+\frac{1001}{10}+\frac{1001}{15}+\frac{143}{3}+\frac{143}{4}\)

\(D=\frac{5005}{12}\)

đáp án là 5005/12 nhé bạn

tích cho mik nha

\(Rút\)\(gọn:\)\(\frac{1001}{6}+\frac{1001}{10}+\frac{1001}{15}+\frac{143}{3}+\frac{143}{4}\)

\(=\frac{1001}{3}+\frac{1001}{12}=\frac{5005}{12}\)

A = 7/4 . (3333/1212 + 3333/2020 + 3333/3030 + 3333/4242)
A = 7/4 . (11/4 + 33/20 + 11/10 + 11/14)
A = 7/4 . 44/7
A = 11
Chúc bạn học tốt

\(A=\frac{7}{4}.\left(\frac{3333}{1212}+\frac{3333}{2020}+\frac{3333}{4242}\right)\)

\(A=\frac{7}{4}.\left(\frac{33.101}{12.101}+\frac{33.101}{20.101}+\frac{33.101}{42.101}\right)\)

\(A=\frac{7}{4}.\left(\frac{33}{12}+\frac{33}{20}+\frac{33}{42}\right)\)

\(A=\frac{7}{4}.33.\left(\frac{1}{12}+\frac{1}{20}+\frac{1}{42}\right)\)

\(A=\frac{7}{4}.33.\left(\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}\right)\)

\(A=\frac{7}{4}.33.\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}\right)\)

\(A=\frac{7}{4}.33.\left(\frac{1}{3}-\frac{1}{6}\right)\)

\(A=\frac{7}{4}.33.\frac{1}{6}\)

\(A=\frac{7.33}{4.6}\)

\(A=\frac{7.3.11}{4.3.2}\)

\(A=\frac{7.11}{4.2}\)

\(A=\frac{77}{8}\)

\(A=\frac{7}{4}.\left(\frac{33}{12}+\frac{33}{20}+\frac{33}{30}+\frac{33}{42}\right)\)

\(=\frac{7}{4}.33.\left(\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}\right)\)

\(=\frac{231}{4}.\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}\right)\)

\(=\frac{231}{4}.\left(\frac{1}{3}-\frac{1}{7}\right)\)

\(=\frac{231}{4}.\frac{4}{21}=11\)