bai 1: Tim x
a) (x-1)^3 =27
b ( 2x +1)^2=25
c) (x-1)^x+2=(x-1)x+4
d) ( 2x-1)^3 =-8
e) 2^2x-2x=96
GIUP MK VOI NHA MK DANG CAN GAP LAM
Giup mk not bai nay , dang gap !
Thuc hien phep tinh:
a, (x -2) ^3 -x(x+1)(x-1) + 6x(x -3)
b, (x-2)(x^2 - 2x +4)(x+2)(x^2 +2x + 4)
Thanks moi ng nha !
BAI 1 TINH
x ^ 2 . x - 2x^3
6 x^2 y . 3 xy - 2y ^2 .x +y
4x^2 + 5x -1 . 2x^3 - 3x
- 8 x^3y + 2 y^4 . 3xy^3 - 2 x^4 + 7y ^4
CAC BAN OI GIUP MINH NHE MINH DANG CAN GAP
tim x biet N thuoc
a) 2-(x+3)=1+2+3+4+5+..............+99
b)(x+1)+(x+2)+(x+3)+(x+4)+...............+(x+100)=5750
giup mk nha cac ban , mk dang can gap lam
a) 2-(x+3) = 1+2+3+...+99
1+2+3+...+99 → có 99 số hạng
2-(x+3) = (1+99).99 : 2
2-(x+3) = 4950
x+3 = 2 + 4950
x+3 = 4952
x = 4952 - 3
x = 4949
b) (x+1)+(x+2)+...+(x+100) = 5750
→ có 100 cặp
(x+x+x+...+x) + ( 1+2+3+...+100 ) = 5750
=> 100x + 5050 = 5750
100x = 5750 - 5050
100x = 700
x = 700 : 100
x = 7
0o0 Nguyễn Đoàn Tuyết Vy 0o0 bà kêu tui học tốt có nghĩa là học giốt đúng ko
b)(x+1)+(x+2)+(x+3)+(x+4)+...............+(x+100)=5750
(x+x+x+x+...+x) + (1+2+3+4+...+100) = 5750
100x + 5050 = 5750
100x = 5750 - 5050
100x = 700
x = 700 : 100
x = 7
Vậy ...
Tim x thuoc \(Q\):
a) |5.(2x+3)|+|2.(2x+3)|+|2x+3|=16
b)|x2+|6x-2|| =x2+4
c)3x -|2x+1|=2
d)2.|x2+|x-1||=2x2+2
Cac anh chi CTV va cac ban giup mk nhe, mk dg can gap lem, nhanh len nhoa!! Tks truoc
\(\left|5\left(2x+3\right)\right|+\left|2\left(2x+3\right)\right|+\left|2x+3\right|=16\)
\(=8\left(2x+3\right)=16\)
\(\Rightarrow2x+3=2\)
\(\Rightarrow x=-\frac{1}{2}\)
tim m biet
a) (x^2-x+1)x-(x+1)x^2+m= -2x^2+x+5
b) -x^2(x^2+x+1+2)= -x^4-x^3-x^2+m
giup vs nhanh mk dag can gap
Tim x
A,740:(x+10)=102-2×13
B,12(x-1):3=43+23
C,10+2x:42011=42013
Giup minh voi minh dang gap lam !!!!
a) 740:(x+10)=102-2x13
=>740:(x+10)=100-2x13
=>740:(x+10)=1274
=>x=10,5808477237048(6)
6 là chu kì (có nghĩa là 6soos 6 kéo dài mãi mãi không giới hạn)
Tim x biet /x-3/+/3x+4/=/2x+1/
Giup to vs! Cam on cac cau nhieu lam
Tra loi nhanh nhe to dang can gap
cho 2 bieu thuc A=x+x^2/2-x va B=2x/x+1+3/x-2-2x^2+1/x^2-x-2 a, tinh gia tri cua A khi /2x-3/=1 b,tim dieu kien xac dinh va rut gon bieu thuc B c,tim so nguyen x de P=A.B dat gia tri lon nhat
mk dang can gap
a:
ĐKXĐ: x<>2
|2x-3|=1
=>\(\left[{}\begin{matrix}2x-3=1\\2x-3=-1\end{matrix}\right.\)
=>\(\left[{}\begin{matrix}x=2\left(loại\right)\\x=1\left(nhận\right)\end{matrix}\right.\)
Thay x=1 vào A, ta được:
\(A=\dfrac{1+1^2}{2-1}=\dfrac{2}{1}=2\)
b: ĐKXĐ: \(x\notin\left\{-1;2\right\}\)
\(B=\dfrac{2x}{x+1}+\dfrac{3}{x-2}-\dfrac{2x^2+1}{x^2-x-2}\)
\(=\dfrac{2x}{x+1}+\dfrac{3}{x-2}-\dfrac{2x^2+1}{\left(x-2\right)\left(x+1\right)}\)
\(=\dfrac{2x\left(x-2\right)+3\left(x+1\right)-2x^2-1}{\left(x+1\right)\left(x-2\right)}\)
\(=\dfrac{2x^2-4x+3x+3-2x^2-1}{\left(x+1\right)\left(x-2\right)}\)
\(=\dfrac{-x+2}{\left(x+1\right)\left(x-2\right)}=-\dfrac{1}{x+1}\)
c: \(P=A\cdot B=\dfrac{-1}{x+1}\cdot\dfrac{x\left(x+1\right)}{2-x}=\dfrac{x}{x-2}\)
\(=\dfrac{x-2+2}{x-2}=1+\dfrac{2}{x-2}\)
Để P lớn nhất thì \(\dfrac{2}{x-2}\) max
=>x-2=1
=>x=3(nhận)
Cho:
Q=(\(\dfrac{2x-x^2}{2x^2+8}\)-\(\dfrac{2x^2}{x^3-2x^2+4x-8}\)).(\(\dfrac{2}{x^2}\)+\(\dfrac{1-x}{x}\))
a, Tim dieu kien xac dinh
b, rut on q
c, Tinh Q khi x=2017
d, Tim x thuoc Z de Q thuoc Z
GIUP MINH VOI CAN GAP LAM!!!