a)120-3(x+4)=23

=>3(x+4)=120-23

=>3(x+4)=97

=>x+4=97:3

=>x+4=\(\frac{97}{3}\)

=>x=\(\frac{97}{3}\)-4

=>x=\(\frac{85}{3}\)

Vậy x=\(\frac{85}{3}\)

b)[(4x+28).3+55]:5=35

=>(4x+28).3+55=35.5

=>(4x+28).3+55=175

=>(4x+28).3=175-55

=>(4x+28).3=120

=>4x+28=120:3

=>4x+28=40

=>4x=40-28

=>4x=12

=>x=12:4

=>x=3

Vậyx= 3

c)\((12x-4^3).8^3=4.8^4\)

=>\(12x-64=4.8^4:8^3\)

=>12x-64=4.8

=>12x-64=32

=>12x=96

=>x=96:12

=>x=8

Vậy x=8

d)720:[41-(2x-5)]=2³.5

=>720:[41-2x-5)]=40

=>41-(2x-5)=720:40

=>41-(2x-5)=18

=>2x-5=41-18

=>2x-5=23

=>2x=23+5

=>2x=28

=>x=28:;2

=>x=14

Vậy x=14

a, 120 - 3 [ x+4]=23

     3 [x+4]= 120-23 = 97

      3x = 97-4

      3x= 93

        x= 93:3

        x=31

em bt làm mỗi bài này thui mà ko bt đúng ko

a) 120 - 3(x + 4) = 23

=> 3(x + 4) = 120 - 23 = 97

=> x + 4 = 97 : 3

=> x + 4 = 97/3

=> x = 97/3 - 4 = 85/3

b) [(4x + 28) . 3 + 55] : 5 = 35

=> [(4x + 28) . 3 + 55] = 175

=> (4x + 28).3 + 55 = 175

=> (4x + 28).3 = 120

=> 4x + 28 = 40

=> 4x = 12

=> x = 3

c) (12x - 4³).8³ = 4.8⁴

=> (12x - 4³) = \(\frac{4\cdot8^4}{8^3}=4\cdot8=32\)

=> 12x - 64 = 32

=> 12x = 96

=> x = 96 : 12 = 8

d) Tương tự

Chị cũng đang ko biét ở bài này nè. Hu hu

\(1)\frac{1}{5}+\frac{2}{11}< \frac{x}{55}< \frac{2}{5}+\frac{1}{55}\)

\(\Rightarrow\frac{11}{55}+\frac{10}{55}< \frac{x}{55}< \frac{22}{55}+\frac{1}{55}\)

\(\Rightarrow\frac{21}{55}< \frac{x}{55}< \frac{23}{55}\)

\(\Rightarrow21< x< 23\)

\(\Rightarrow x=22\)

\(2)\frac{11}{3}+\frac{-19}{6}+\frac{-15}{2}\le x\le\frac{19}{12}+\frac{-5}{4}+\frac{-10}{3}\)

\(\Rightarrow\frac{22}{6}+\frac{-19}{6}+\frac{-45}{6}\le x\le\frac{19}{12}+\frac{-15}{12}+\frac{-40}{12}\)

\(\Rightarrow\frac{22+\left[-19\right]+\left[-45\right]}{6}\le x\le\frac{19+\left[-15\right]+\left[-40\right]}{12}\)

\(=\frac{-42}{6}\le x\le\frac{-36}{12}\)

\(\Rightarrow-7\le x\le-3\)

\(\Rightarrow x\in\left\{-7;-6;-5;-4;-3\right\}\)

\(3)\frac{1}{2}+\frac{1}{3}+\frac{1}{6}\le x\le\frac{-1}{2}+2+\frac{5}{2}\)

\(\Rightarrow\frac{3}{6}+\frac{2}{6}+\frac{1}{6}\le x\le\frac{-1}{2}+\frac{5}{2}+2\)

\(\Rightarrow1\le x\le2+2\)

\(\Rightarrow1\le x\le4\)

\(\Rightarrow x\in\left\{1;2;3;4\right\}\)

Bài này khử mẫu sẽ tính nhanh hơn.

\(\frac{\left[\left(4x+28\right)3+55\right]}{5}=5\)

\(\Leftrightarrow\frac{\left[\left(4x+28\right)3+55\right]}{5}=\frac{25}{5}\)

\(\Leftrightarrow\left[\left(4x+28\right)3+55\right]=25\)

\(\Leftrightarrow\left[12x+84+55\right]=25\)

\(\Leftrightarrow12x=25-84-55\)(chuyển vế đổi dấu)

\(\Leftrightarrow12x=-114\Leftrightarrow x=-\frac{19}{2}\)

\(\frac{\left[\left(4x+28\right).3+55\right]}{5}=5\)

\(\Leftrightarrow\left(4x+28\right).3+55=25\)

\(\Leftrightarrow\left(4x+28\right).3=-30\)

\(\Leftrightarrow4x+28=-10\)

\(\Leftrightarrow4x=-38\)

\(\Leftrightarrow x=-9,5\)

Vậy\(x=-9,5\)

Ddaeng

(4x+28)*3+55=5*5

(4x+28)*3+55=25

(4x+28)*3=25-55

(4x+28)*3=-30

4x+28=-30:3

4x+28=-10

4x=-10-28

4x=-38

x=-38:4

x=-9,5

⇒ ( 4x + 28 ) . 3 + 55  = 35 . 5

 ⇒ ( 4x + 28 ) . 3 + 55 = 175

  ⇒ ( 4x + 28 ) . 3 = 175 - 55

  ⇒ ( 4x + 28 ) .3 = 120

   ⇒  4x + 28 = 120 : 3

    ⇒ 4x + 28 = 40

   ⇒  4x = 40 -  28

    ⇒ 4x = 12

     ⇒ x = 12: 4

⇔ x = 3.

Vậy x= 3.

\(\left[\left(4x+28\right)\times3+55\right]\div5=35\)

\(\left(4x+28\right)\times3+55=175\)

\(12x+84+55=175\)

\(12x=175-55-84\)

\(12x=36\)

\(x=3\)

`@` `\text {Ans}`

`\downarrow`

`b)`

\([(4x+28).3+55] \div 5=35\)

`=> (4x + 28) * 3 + 55 = 35 * 5`

`=> (4x + 28)*3 + 55 = 175`

`=> (4x + 28)*3 = 175 - 55`

`=> (4x + 28)*3 =120`

`=> 4x + 28 = 120 \div 3`

`=> 4x + 28 = 40`

`=> 4x = 40 - 28`

`=> 4x = 12`

`=> x = 12 \div 4`

`=>x = 3`

Vậy, `x = 3.`

=>[12x+84+55]=175

=>12x=175-84-55=120-84=36

=>x=36/12=3

<=>[12x+84+55]:5=35

<=>[12x+139]:5=35

<=>12x+139=35.5

<=>12x=175-139

<=>x=3