\(5^x+5^{x+1}+5^{x+2}=100.....0:2^{18}\)
cai 100....00 la 14 chu so 0 nhe
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tim x
\(^{ }5^x.5^{\left(x+1\right)}.5^{\left(x+2\right)}_{ }< ,=100...0:2^{18}_{_{ }}\)
100...0=18 chu so 0
ta có : \(5^x.5^{\left(x+1\right)}.5^{\left(x+2\right)}\le\dfrac{100...0}{2^{18}}\) \(\Leftrightarrow5^{3x+3}\le\dfrac{10^{18}}{2^{18}}=5^{18}\)
\(\)\(\Leftrightarrow3x+3\le18\Leftrightarrow x\le5\) vậy \(x\le5\)
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Tìm z thuộc N biết, 5x . 5x+1 . 5x+2 < 100...00 :2^18 ma 100...00 co 18 cs 0
5x . 5x+1.5x+2<1018:218
=>53x+3<518
=>x<6
=>x={0;1;2;3;4;5}
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tim x thuoc N ,sao cho : 5x.5x+1.5x+2_< 100...0 : 218 (18 chu so 0)
tim x
a) 16x < 1284
b) 5x.5x+1.5x+2 < 100...0 : 218 ( 100..0 co 18 chu so 0 )
tim x
16x <1284
5x.5x+1.5x+2 < 100...0 : 218 ( 100...0 co 10 chu so 0 )
16x<1284
=>(24)x<(27)4
=>24x<228
=>4x<28
=>x<7
=>x=0;1;2;3;4;5;6
vậy x=0;1;2;3;4;5;6
b,=>5x.5x+1.5x+2<1010:218
=>53x+3<510.210:218
=>53x+3<510.28
=>53x+3:510<28
=>53(x+1)-10<256<54
=>3(x+1)-10<4
=>3(x+1)<4+10
=>x+1<14/3<5
=>x<4
=>x=0;1;2;3
vậy x=0;1;2;3
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16^x < 128^4
=> 2^4x < 2^7.4
=> 2 ^4x < 2^28
=> 4x < 28
=> x < 7
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16x<1284
=>(24)x<(27)4
=>24x<228
=>4x<28
=>x<7
=>x=0;1;2;3;4;5;6
vậy x=0;1;2;3;4;5;6
b,=>5x.5x+1.5x+2<1010:218
=>53x+3<510.210:218
=>53x+3<510.28
=>53x+3:510<28
=>53(x+1)-10<256<54
=>3(x+1)-10<4
=>3(x+1)<4+10
=>x+1<14/3<5
=>x<4
=>x=0;1;2;3
vậy x=0;1;2;3
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Tìm x biết :
5x . 5x+1 . 5x+2 < 100.......00 ( có 18 chữ số 0 ) : 218
Tìm x biết 5x . 5x + 1 . 5x + 2 \(\le\) 100.....00 ( 18 chữ số 0 ) : 218
Ta có \(5^{3x+3}\le10^{18}\div2^{18}\Rightarrow5^{3x+3}\le5^{18}\)
\(\Rightarrow3x+3\le18\) ; \(x\le5\)
\(\Rightarrow x\in\left\{0;1;2;3;4;5\right\}\)
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Tìm x:
a) 1 +3+5+7+9+...+(2x+1)=361
b) 2+4+6+...+2x=156
c) 2x.2x+1.2x+2 =100...00:518 {18 chữ số 0}
tim x
5^x*5^(x+1)*5^(x+2) < hoặc = 100....0 (18 số 0 )/ 2^18
Ta có
\(5^x.5^{x+1}.5^{x+2}\le10^{18}:2^{18}=>5^{3x+3}\le5^{18}=>3x+3\le18=>x\le5\)
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