075 : 4,5 = \(\frac{1}{15}:\left(2x\right)\)
Tìm x, biết:
075 : 4,5 = \(\dfrac{1}{15}:\left(2x\right)\)
0,75 : 4,5 = \(\dfrac{1}{15}\) : (2x)
\(\Rightarrow\) \(\dfrac{1}{6}\) = \(\dfrac{1}{30}\) : x
\(\Rightarrow\) \(\dfrac{1}{30}\) : \(\dfrac{1}{6}\) = x
\(\Rightarrow\) x = \(\dfrac{1}{5}\)
0,75 : 4,5 = 1/15 : (2x)
1/6 = 1/15 : (2x)
(2x) = 1/15 : 1/6
2x = 2/5
x = 2/5 : 2
x = 1/5
Vậy x = 1/5
chúc bn hc tốt môn toán
đó là đáp án đúng đó ạk
-4x(x-5)-2x(8-2x)=-3
\(\frac{x-1}{-15}=\frac{-60}{x-1}\)
\(\left(\frac{1}{4}x-1\right)+\left(\frac{5}{6}x-2\right)-\left(\frac{3}{8}x+1\right)=4,5\)
a/ -4x(x - 5) - 2x(8 - 2x) = -3
=> -4x2 + 20x - 16x + 4x2 = -3
=> 4x = -3
=> x = -3/4
b/ \(\frac{x-1}{-15}=-\frac{60}{x-1}\Rightarrow\left(x-1\right)^2=\left(-60\right)\left(-15\right)\)
\(\Rightarrow\left(x-1\right)^2=900\Rightarrow\orbr{\begin{cases}x-1=30\\x-1=-30\end{cases}\Rightarrow\orbr{\begin{cases}x=31\\x=-29\end{cases}}}\)
Vậy x = -29 , x = 31
Các bn ơi! Cứu mk vs! Ngày mai có Toán òiCó câu tính mãi ko ra.Nhanh lên nha.Mk xin các bn đó.Mk đang cần gấp
Bài 1: Tìm x trg mỗi tỉ lệ thức sau
a)\(075:4,5=\frac{1}{15}:\left(2x\right)\)
b)\(\left(2,5-3x\right):\frac{5}{3}=\left(\frac{8}{5}+2x\right):\left(-\frac{8}{17}\right)\)
Bài 2:Bn Hùng đi bộ,bn Liên đi xe đạp.Tỉ số vận tốc của bn Hùng vs vận tốc của bn Liên là 2:6,1.Hỏi trg thời gian bn Hùng đi đc 5m thì bn Liên đi đc bao nhiêu m?
a) 0,75 : 4,5 = \(\frac{1}{15}\) : 2x
=> \(\frac{0,75}{4,5}\) = \(\frac{\frac{1}{15}}{2x}\)
=> 0,75 . 2x = \(\frac{1}{15}\) . 4,5
=> 0,75 . 2x = 0,3
=> 2x = 0,3 : 0,75
=> 2x = 0,4
=> x = 0,4 : 2
=>x = 0,2
\(\left(4,5-2x\right).\left(-3\frac{2}{3}\right)=\frac{11}{15}\)
\(\backslash34-x\backslash=\left(-3\right)^4\)
\(\left(4x^2-1\right)\left(\backslash x\backslash-\frac{2}{3}\right)=0\)
\(\frac{3}{5}x-\frac{1}{2}x=\frac{-7}{2}\)
Tìm x trong mỗi tỉ lệ thức sau:
c) 0,75: 4,5=\(\frac{1}{15}:\left(2x\right)\)
Ta có: 0,75:4,5= \(\frac{1}{15}\):(2x)
suy ra \(\frac{1}{6}\)=\(\frac{1}{15}\):(2x)
suy ra 2x = \(\frac{1}{15}:\frac{1}{6}\)
suy ra 2x= \(\frac{2}{5}\)
suy ra x= \(\frac{1}{5}\)
Vậy x=...
Tìm x, biết:
a, 2x-10-[3x-14-(4-5x)-2x] = 2
b,\(\left(\frac{1}{4}x-1\right)+\left(\frac{5}{6}x-2\right)-\left(\frac{3}{8}x+1\right)=4,5\)
a/ 2x - 10 - [3x - 14 - (4 - 5x) - 2x] = 2
=> 2x - 10 - (3x - 14 - 4 + 5x - 2x) = 2
=> 2x - 10 - 3x + 14 + 4 - 5x + 2x = 2
=> -4x + 6 = 0
=> -4x = -6
=> x = 3/2
b/ \(\left(\frac{1}{4}x-1\right)+\left(\frac{5}{6}x-2\right)-\left(\frac{3}{8}x+1\right)=4,5\)
\(\Rightarrow\frac{1}{4}x-1+\frac{5}{6}x-2-\frac{3}{8}x-1-\frac{9}{2}=0\)
\(\Rightarrow\frac{17}{24}x-\frac{17}{2}=0\)
\(\Rightarrow\frac{17}{24}x=\frac{17}{2}\)
\(\Rightarrow x=12\)
\(3,2.\frac{15}{16}-\left(75\%+\frac{2}{7}\right):\left(-1\frac{1}{28}\right)\)
\(\left(0,25+12,5-\frac{5}{16}\right):\left[12-\frac{7}{12}:\left(\frac{3}{8}-\frac{1}{12}\right)\right]\)
\(\left(\frac{-3}{5}+\frac{5}{11}\right):\frac{-3}{7}+\left(\frac{-2}{5}+\frac{6}{5}\right):\frac{-3}{7}\)
\(14,5-\frac{8}{9}:\left(35-34\frac{8}{9}\right).\frac{9}{8}\)
\(1\frac{1}{15}-\left(\frac{1}{15}+\frac{4}{9}:\frac{-2}{3}-\frac{28}{16}.\frac{6}{35}\right)-\frac{3}{10}\)
Tìm x
\(\left(4,5-2x\right)\left(-3\frac{2}{3}\right)=\frac{11}{15}\)
\(\backslash34-x\backslash=\left(-3\right)^4\)
\(\left(4x^2-1\right)\left(\text{\x}\backslash-\frac{2}{3}\right)=0\)
\(\frac{3}{5}x-\frac{1}{2}\)\(x=\frac{-7}{20}\)
\(=\frac{16}{5}.\frac{15}{16}-\left(\frac{3}{4}+\frac{2}{7}\right):\left(\frac{-29}{28}\right)\)
\(=3-\left(\frac{21}{28}+\frac{8}{28}\right):\left(\frac{-29}{28}\right)\)
\(=3-\left(\frac{29}{28}\right).\left(\frac{-28}{29}\right)\)
\(=3-\left(-1\right)\)
\(=4\)
b) \(=\left(\frac{1}{4}+\frac{25}{2}-\frac{5}{16}\right):\left(12-\frac{7}{12}:\left(\frac{3}{8}-\frac{1}{12}\right)\right)\)
\(=\left(\frac{4}{16}+\frac{200}{16}-\frac{5}{16}\right):\left(12-\frac{7}{12}:\left(\frac{3.3}{2.3.4}-\frac{2}{2.3.4}\right)\right)\)
\(=\left(\frac{199}{16}\right):\left(12-\frac{7}{12}:\left(\frac{9}{24}-\frac{2}{24}\right)\right)\)
\(=\frac{199}{16}:\left(12-\frac{7}{12}.\frac{24}{7}\right)\)
\(=\frac{199}{16}:\left(12-2\right)\)
\(=\frac{199}{16}:10\)
\(=\frac{199}{160}\)
c) \(\left(\frac{-3}{5}+\frac{5}{11}\right):\frac{-3}{7}+\left(\frac{-2}{5}+\frac{6}{5}\right):\frac{-3}{7}\)
\(\left(\frac{-33}{55}+\frac{25}{55}\right):\frac{-3}{7}+\left(\frac{4}{5}\right):\frac{-3}{7}\)
\(\left(\frac{-8}{55}\right).\frac{-7}{3}+\frac{4}{5}.\frac{-7}{3}\)
\(\frac{-7}{3}\left(\frac{-8}{55}+\frac{4}{5}\right)\)
\(\frac{-7}{3}.\frac{36}{55}=\frac{-84}{55}\)
nhớ làm giúp mình nhá mai mình phải đi học r :<
\(\left(4,5-2x\right):\frac{3}{4}=1\frac{1}{3}\)
\(\left(4,5-2x\right):\frac{3}{4}=1\frac{1}{3}\)
\(\Leftrightarrow\left(4,5-2x\right):\frac{3}{4}=\frac{4}{3}\)
\(\Leftrightarrow4,5-2x=1\)
\(\Leftrightarrow2x=3,5\)
\(\Leftrightarrow x=1,75\)
\(\left(4,5-2x\right):\frac{3}{4}=1\frac{1}{3}\)
\(4,5-2x=1\frac{1}{3}\cdot\frac{3}{4}\)
\(4,5-2x=1\)
\(2x=4,5-1=3,5\)
\(x=3,5:2=1,75\)
Vậy .........................
\(\left(4,5-2x\right)\)\(:\frac{3}{4}=1\frac{1}{3}\)
\(\left(4,5-2x\right)=\)\(1\frac{1}{3}x\frac{3}{4}\)
\(\left(4,5-2x\right)=1\)
\(2x=1+4,5\)
\(2x=5,5\)
\(x=5,5:2\)
\(x=2,75\)
Vậy x = 2,75
Học tốt~~~
tìm x
\(|x+3|\div\left(-15\right)=\frac{1}{3}\)
\(|4,5-2x|\cdot(-1\frac{4}{7})=\frac{-11}{14}\)
giúp mình với mai mình nộp rồi
a) \(\left|x+3\right|:\left(-15\right)=\frac{1}{3}\)
\(\left|x+3\right|=-5\)
=> không tìm được x
b) \(\left|4,5-2x\right|.\left(-1\frac{4}{7}\right)=-\frac{11}{14}\)
\(\left|4,5-2x\right|=2\)
TH1: 4,5 - 2x = 2
2x = 2,5
x = 1,25
TH2: 4,5 - 2x = -2
2x = 6,5
x = 3,25
KL:...