Tìm x:
5X+1 - 5X = 500
Tìm số tự nhiên x, biết:
a, 3 x - 2 3 = 2 . 32
b, 5 x + 1 - 5 x = 500
a, 3 x - 2 3 = 2 . 32
3 x - 2 3 = 64
3 x - 2 3 = 4 3
3 x - 2 = 4 ⇔ x = 2
b, 5 x + 1 - 5 x = 500
5 x . 5 - 5 x = 500
5 x . ( 5 - 1 ) = 500
5 x . 4 = 500
5 x = 125 = 5 3
x = 3
Câu 1, tìm x:
a,(5x-1)^2-(5x+4)(5x-4)=7
b,(4x-1)^2-(2x+3)^2+5.(x+2)^2+3.(x-2).(x+2)=500
(giúp mình với, mình đang cần gấp)
Tìm x biết :
x^2 + 5x = 500
x^2 + 5x = 500
<=> x^2 + 5x - 500 = 0
<=> (x - 20)(x + 25) = 0
<=> x - 20 = 0 hoặc x - 25 = 0
x = 0 + 20 x = 0 - 25
x = 20 x = -25
=> x = 20 hoặc x = -25
Họ Và Tên chỗ x - 25 = 0 sao bằng -25 vậy ???
Chetme :)) T nhầm :)) cảm ơn tv của team trash đã nhắc =)) sửa lại
x + 25 = 0
x = 0 - 25
x = -25
Tìm x biết
a, \(\left(5x-1\right)^2-\left(5x-4\right)\left(5x+4\right)=7\)
b,\(\left(4x-1\right)^2-\left(2x+3\right)^2+5\left(x+2\right)^2+3\left(x-2\right)\left(x+2\right)=500\)
\(\left(5x-1\right)^2-\left(5x-4\right)\left(5x+4\right)=7\)
\(25x^2-10x+1-25x^2+16=7\)
\(17-10x=7\)
\(10x=10\)
\(x=1\)
1.tìm x:
a.(5x-1)2-(5x-4)\(\times\)(5x+4)=7
b.(4x-1)2-(2x+3)2\(\times\)5\(\times\)(x+2)2+3\(\times\)(x-2)\(\times\)(x+2)=500
a)\(\left(5x-1\right)^2-\left(5x-4\right)\left(5x+4\right)=7\)
\(\Leftrightarrow25x^2-10x+1-25x^2+16=7\)
\(\Leftrightarrow-10x=-10\)
\(\Leftrightarrow x=1\)
b) k hiểu đề
Tìm x biết
(5x-1)2-(5x-4)(5x+4)=7
`(5x-1)^2-(5x-4)(5x+4)=7`
`\Leftrightarrow 25x^2-10x+1-25x^2+16-7=0`
`\Leftrightarrow -10x+10=0`
`\Leftrightarrow x=1`
Tìm x biết a) (x^2-4x+5)_(x^2-2x+1)=3 lớp 7
b)(4x^3-5X^2+3x-1)+(3-5x+5x^2-4x^3)=2
c)(3x-2)-(5x+4)=(x-3)-(X+5)
a, \(-4x+5+2x-1=3\Leftrightarrow-2x=-1\Leftrightarrow x=\dfrac{1}{2}\)
b, \(-2x+2=2\Leftrightarrow x=0\)
c, \(-2x-6=-8\Leftrightarrow x=1\)
tìm x biết: (5x+1)^2-(5x+3)(5x-3)=30
\(\left(5x+1\right)^2-\left(5x+3\right)\left(5x-3\right)=30\)
\(25x^2+10x+1-\left(25x^2-9\right)=30\)
\(25x^2+10x+1-25x^2+9=30\)
\(10x+10=30\)
\(10x=20\)
\(x=2\)
(5x+1)2-(5x+3)(5x-3)=30
=>25x2+10x+1-25x2+9=30
=>(25x2-25x2)+10x+1+9=30
=>10x+10=30
=>10x=20
=>x=2
1. Tìm x
a. (5x-7)(x-9)-(-x+3)(-5x+2)= 2x(x-4)-(x-1)(2x+3)
b. (x-3)(-x+10)+(x-8)(x+3)= (5x^2-1)(x+3)-5x^3-15x^2
ta có
a. (5x-7)(x-9)-(-x+3)(-5x+2)= 2x(x-4)-(x-1)(2x+3)
\(\Leftrightarrow5x^2-52x+63-\left(5x^2-17x+6\right)=2x^2-8x-\left(2x^2+x-3\right)\)
\(\Leftrightarrow-35x+57=-9x+3\Leftrightarrow26x=54\Leftrightarrow x=\frac{27}{13}\)
b. (x-3)(-x+10)+(x-8)(x+3)= (5x^2-1)(x+3)-5x^3-15x^2
\(\Leftrightarrow-x^2+13x-30+x^2-5x-24=5x^3+15x^2-x-3-5x^3-15x^2\)
\(\Leftrightarrow8x-54=-x-3\Leftrightarrow9x=51\Leftrightarrow x=\frac{17}{3}\)
tìm x
a) 5x+1)-(5x+3).(5x-3)=30
b) (x-3).(x2+3x+9)+x.(x+2).(2-x)=1
a) (5x+1)2-(5x+3).(5x-3)=30
\(\Leftrightarrow25x^2+10x+1-25x^2+9-30=0\)
\(\Leftrightarrow10x-20=0\)
\(\Leftrightarrow10x=20\)
\(\Leftrightarrow x=2\)
b) (x-3).(x2+3x+9)+x.(x+2).(2-x)=1
\(\Leftrightarrow x^3-3^3+x\left(4-x^2\right)-1=0\)
\(\Leftrightarrow x^3-27+4x-x^3-1=0\)
\(\Leftrightarrow4x-28=0\)
\(\Leftrightarrow4x=28\)
\(\Leftrightarrow x=7\)