Đặt A:

A = \(\frac{4,5:47,375-\left(26\frac{1}{3}-18.0,75\right).2,4:0,88}{17,81:1,37-23\frac{2}{3}:1\frac{5}{6}}\)

= \(\frac{\frac{9}{2}:\left[\frac{379}{8}-\left(\frac{79}{3}-\frac{27}{2}\right).\frac{30}{11}\right]}{13-\frac{71}{3}.\frac{6}{11}}\)

= \(\frac{\frac{9}{2}:\left[\frac{379}{8}-\frac{77}{6}.\frac{30}{11}\right]}{13-\frac{142}{11}}\)

= \(\frac{\frac{9}{2}:\left[\frac{379}{8}-35\right]}{\frac{1}{11}}\)

= \(\left(\frac{9}{2}:\frac{99}{8}\right).1\)

= \(\frac{4}{11}.11\) = 4

=> A = 4

=4

thui đề mink hỏi mink tự giải vậy

mk làm được rồi G=4

\(\left|2x-27\right|^{2007}+\left(3y+10\right)^{2018}=0\)

Ta  có \(\left|2x-27\right|^{2017}\ge0\forall x;\left(3y+10\right)^{2018}\ge0\forall y\)

\(\Rightarrow\left|2x-27\right|^{2017}+\left(3.y+10\right)^{2018}\ge0\forall x;y\)

\(\Rightarrow\left|2x-17\right|^{2017}+\left(3y+10\right)^{2018}=0\)

\(\Leftrightarrow\hept{\begin{cases}2x-17=0\\3.y+10=0\end{cases}}\)

\(\Leftrightarrow\hept{\begin{cases}x=\frac{17}{2}\\y=-\frac{10}{3}\end{cases}}\)

ấn mt ấy dễ mà mình ra \(\frac{260}{7733}\)

\(\frac{4,5\div\left[47,735-\left(26\frac{1}{3}-18.0,75\right).2,4\div0,88\right]}{17,81\div1,37-23\frac{2}{3}\div1\frac{5}{6}}\)

\(=\frac{4,5\div\left[47,735-\left(\frac{79}{3}-\frac{27}{2}\right)\cdot\frac{30}{11}\right]}{13-\frac{142}{11}}\)

\(=\frac{4,5\div\left[47,735-\frac{77}{6}\cdot\frac{30}{11}\right]}{\frac{1}{11}}=\frac{4,5\div\left[47,735-35\right]}{\frac{1}{11}}\)

\(=\frac{4,5\div12,735}{\frac{1}{11}}=\frac{100}{283}\div\frac{1}{11}=\frac{1100}{283}\)