Những câu hỏi liên quan
Nguyễn Lan
Xem chi tiết
soyeon_Tiểubàng giải
8 tháng 9 2016 lúc 20:41

\(A=\frac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}\)

\(A=\frac{\left(2^2\right)^5.\left(3^2\right)^4-2.\left(2.3\right)^9}{2^{10}.3^8+\left(2.3\right)^8.2^2.5}\)

\(A=\frac{2^{10}.3^8-2.2^9.3^9}{2^{10}.3^8+2^8.3^8.2^2.5}\)

\(A=\frac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+2^{10}.3^8.5}\)

\(A=\frac{2^{10}.3^8.\left(1-3\right)}{2^{10}.3^8.\left(1+5\right)}\)

\(A=\frac{2^{10}.3^8.\left(-2\right)}{2^{10}.3^8.6}\)

\(A=-\frac{2^{11}.3^8}{2^{10}.3^8.2.3}=-\frac{2^{11}.3^8}{2^{11}.3^9}=-\frac{1}{3}\)

Haruno :3
Xem chi tiết
Nguyễn Lê Phước Thịnh
20 tháng 9 2021 lúc 21:44

\(A=\dfrac{4^5\cdot9^4-2\cdot6^9}{2^{10}\cdot3^8+6^8\cdot20}\)

\(=\dfrac{2^{10}\cdot3^8-2^{10}\cdot3^9}{2^{10}\cdot3^8+3^8\cdot2^{10}\cdot5}\)

\(=\dfrac{2^{10}\cdot3^8\left(1-3\right)}{2^{10}\cdot3^8\cdot\left(1+5\right)}\)

\(=-\dfrac{2}{6}=-\dfrac{1}{3}\)

HwangJungeum
Xem chi tiết
tran cam tu
17 tháng 11 2018 lúc 21:21

=\(\frac{2^{10}.3^8-2.2^9.3^9}{2^{10}.3^8+2^8.3^8.2^2.5}\)

=\(\frac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+2^{10}.3^8.5}\)

Le Minh Anh
Xem chi tiết
Nguyen Ngoc Huyen
Xem chi tiết
Le Thi Khanh Huyen
24 tháng 6 2016 lúc 20:46

\(A=\frac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}\)

\(=\frac{2^{10}.3^8-2.2^9.3^9}{2^{10}.3^8+2^8.3^8.2^2.5}\)

\(=\frac{2^{10}.3^8-2^{10}.3^9}{2^{10}.2^8+2^{10}.3^8.5}\)

\(=\frac{2^{10}.3^8\left(1-3\right)}{2^{10}.3^8\left(1+5\right)}\)

\(=\frac{-2}{6}=-\frac{1}{3}\)

Hậu Duệ Mặt Trời
24 tháng 6 2016 lúc 20:52

\(A=\frac{\left(2^2\right)^5.\left(3^2\right)^4-2.2^9.3^9}{2^{10}.3^8+2^8.3^8.2^2.5}\)

\(A=\frac{2^{10}.3^8-2^{11}.3^9}{2^{10}.3^8+2^{10}.3^8.5}\)

\(A=\frac{2^{10}.3^8.\left(1-2.3\right)}{2^{10}.3^8.\left(1+5\right)}\)

\(A=\frac{1-6}{6}\)

\(A=\frac{-5}{6}\)

duyên
Xem chi tiết
Nguyễn Phương HÀ
12 tháng 8 2016 lúc 20:44

\(\frac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}\)

=\(\frac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+2^{10}.5.3^8}=\frac{2^{10}.3^8\left(1-3\right)}{2^{10}.3^8\left(1+5\right)}=-\frac{2}{6}=-\frac{1}{3}\)

KUNG FU PANDA 3
Xem chi tiết
Mai Hương 2003
6 tháng 11 2016 lúc 15:09

Bằng 1/6

Nguyễn Thị Bích Ngọc
Xem chi tiết
Đỗ Thu Giang
14 tháng 7 2016 lúc 20:54

\(A=\frac{\left(2^2\right)^5.\left(3^2\right)^4-2.\left(2.3\right)^9}{2^{10}.3^8+\left(2.3\right)^8.2^2.5}=\frac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+2^{10}.3^8.5}=\frac{2^{10}.3^8\left(1-3\right)}{2^{10}.3^8\left(1+5\right)}=\frac{-2}{6}=\frac{-1}{3}\)

Phan Thanh Tịnh
14 tháng 7 2016 lúc 21:04

A = \(\frac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}=\frac{\left(2^2\right)^5.\left(3^2\right)^4-2.\left(2.3\right)^9}{2^{10}.3^8+\left(2.3\right)^8.2^2.5}=\frac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+2^{10}.3^8.5}\)\(=\frac{2^{10}.3^8.\left(1-3\right)}{2^{10}.3^8.\left(1+5\right)}=\frac{-2}{6}=\frac{-1}{3}\)

Trương Quỳnh Hoa
Xem chi tiết