\(9x^4-15x^3-6x^2+5\)

\(=3x^2\left(3x^2-5x\right)-6x^2+5\)

\(=3x^2.2-6x^2+5\)

\(=6x^2-6x^2+5\)

\(=5\)

\(9x^4-15x^3-6x^2+5\)

\(=3x^2\left(3x^2-5x\right)-6x^2+5\)

\(=3x^2.2-6x^2+5\)

\(=6x^2-6x^2+5\)

\(=5\)

Bài 1: 

Ta có: 

\(A=9x^4-15x^3-6x^2+5=3x^2\left(3x^2-5x\right)-6x^2+5=3x^2.2-6x^2+5=6x^2-6x^2+5=5\)

Vậy,  \(A=5\)

Bài 2: Ta có:

\(3^{15}+3^{16}+3^{17}=3^{15}+3^{15}.3+3^{15}.3^2=3^{15}.\left(1+3+3^2\right)=3^{15}.13\)

\(\Rightarrow3^{15}.13\)  chia hết cho  \(13\)

Do đó:  \(3^{15}+3^{16}+3^{17}\)  chia hết cho  \(13\)

\(1,\left(x+2\right)\left(x^2-2x+4\right)+\left(x+2\right)^2=0\)

\(\Rightarrow\left(x+2\right)^3+\left(x+2\right)^2=0\)

\(\Rightarrow\left(x+2\right)^2.\left(x+3\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}\left(x+2\right)^2=0\\x+3=0\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x+2=0\\x+3=0\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=-2\\x=-3\end{matrix}\right.\)

Vậy....

\(A=x^2-4x+10=x^2-4x+4+6=\left(x-2\right)^2+6\ge6\)

Vậy GTNN A là 6 khi x - 2 = 0 <=> x = 2 

\(B=\left(1-x\right)\left(3x-4\right)=3x-4-3x^2+4x=-3x^2+7x-4\)

\(=-3\left(x^2-\frac{7}{3}x+\frac{4}{3}\right)=-3\left(x^2-2.\frac{7}{6}x+\frac{49}{36}-\frac{1}{36}\right)=-3\left(x-\frac{7}{6}\right)^2+\frac{1}{12}\ge\frac{1}{12}\)

\(=3\left(x-\frac{7}{6}\right)^2-\frac{1}{12}\le-\frac{1}{12}\)Vậy GTLN B là -1/12 khi x = 7/6 

\(C=3x^2-9x+5=3\left(x^2-3x+\frac{5}{3}\right)=3\left(x^2-2.\frac{3}{2}x+\frac{9}{4}-\frac{7}{12}\right)\)

\(=3\left(x-\frac{3}{2}\right)^2-\frac{7}{4}\ge-\frac{7}{4}\)Vậy GTNN C là -7/4 khi x = 3/2 

\(D=-2x^2+5x+2=-2\left(x^2-\frac{5}{2}x-1\right)=-2\left(x^2-2.\frac{5}{4}x+\frac{25}{16}-\frac{41}{16}\right)\)

\(=-2\left(x-\frac{5}{4}\right)^2+\frac{21}{8}\le\frac{21}{8}\)Vậy GTLN D là 21/8 khi x = 5/4 

a/15.91,5+150.0.85

=15.91,5+15.3,5

=15(91,5+8,5)

=15.100=1500

b/52.143-52.39-8.26

=52.143-52.39-4.52

=52(143-39-4)

=52.100=5200

c/9x^4-15x^3-6x^2+5 tại 3x^2-5x=2

Ta có :9x⁴-15x³-6x²+5=3x²(3x²-5x-2)+5 (1)

3x²-5x=2=>3x²-5x-2=0 (2)

thay(2) vào (1), ta được : 3x².0+5=5

26:

A=12x^2+10x-6x-5-(12x^2-8x+3x-2)

=12x^2+4x-5-12x^2+5x+2

=9x-3

Khi x=-2 thì A=-18-3=-21

25:

b: \(\left(y-3\right)\left(y^2+y+1\right)-y\left(y^2-2\right)\)

=y^3+y^2+y-3y^2-3y-3-y^3+2y

=-2y^2-3