\(x+\left(x+1\right)+...+\left(x+2013\right)=2035147\)

\(\Leftrightarrow2014x+2027091=2035147\)

\(\Leftrightarrow2014x=8056\)

hay x=4

x+(x+1)+(x+2)+.....+(x+2013)=2035147

2014x+(2013+1).2013:2=2035147

=> 2014x+2014.2013:2=2035147

=>  2014x+2007006=2035147

=> x=(2035147-2007006):2014

=> x=28141:2014

=> x= ko chia hết

x + (x + 1) + (x + 2) + ... + (x + 2013) = 2035147

2014x + 2013.2014:2 = 2035147

2014x + 2027091 = 2035147

2014x = 2035147 - 2027091

2014x = 8056

x = 8056/2014 = 4

x + (x + 1) + (x + 2) + ... + (x + 2013) = 2035147

2014x + (1 + 2 + ... + 2013) = 2035147

2014x + 2027091 = 2035147

2014x = 8056

x = 4

Số số hạng là (2013-0+1)=2014(số)

Tổng là (0+2013)*2014/2=1007*2013=2027091

=>2014x+2027091=2035147

=>x=4

x + ( x + 1) + ( x + 2 ) +......+( x + 2013 ) = 2035147

2014*x+(1+2+3+...+2013)=2035147

2014*x+2027091=2035147

2014*x=2035147-2027091

2014*x=8056

x=8056/2014

x=4

x+(x+1)+(x+2)+...+(x+2013)=2035147

=> x+x+1+x+2+x+3+...+x+2013=2035147

=>2014x+(1+2+3+...+2013)=2035147

=>2014x+2027091=2035147 (tổng trên bạn tự tính nhé mik không ghi cách tính tổng đâu)

=>2014x=2035147-2027091

=> x =8056/2014

=> x = 4

Vậy x = 4 

X+(X+1)+(X+2)+(X+3)+(X+4)+...+(X+2013)=2035147

Xx2014+(1+2+3+4+5+...+2013)                   =2035147

Xx2014+2027091                                         =2035147

Xx2014                                                         =8056

X                                                                   =4

https://d3.violet.vn//uploads/previews/present/4/139/141/preview.swf

x + ( x + 1) + ( x + 2 ) +......+( x + 2013 ) = 2035147

2014*x+(1+2+3+...+2013)=2035147

2014*x+2027091=2035147

2014*x=2035147-2027091

2014*x=8056

x=8056/2014

x=4

cảm ơn các bạn nha

\(x+\left(x+1\right)+\left(x+2\right)+...\left(x+2013\right)=2035147\)\(47\)

\(2014x+\left(1+2+...+2013\right)2035147\)

\(2014x+2027091=2035147\)

\(2014x=2035147-2027091\)

\(2014x=8056\)

\(x=8056:2014\)

\(x=4\)

x + (x + 1) + (x + 2) + ... + (x + 2013) = 2 035 147

2014x + (1 + 2 + 3 + ... + 2013) = 2 035 147

2014x + 2 026 084 = 2 035 147

2014x = 2 035 147 - 2 026 084

2 014x = 9 063

x = 9 063 : 2 014

x = 4,5

Vậy x = 4,5

=))

b, x + (x + 1) + (x + 2) + ..... + (x + 2013) = 2035147 

x + (x + x + .... + x) + (1 + 2 + .... + 2013) = 2035147 

x + 2013x + 2027091 = 2035147 

2014x = 2035147 - 2027091 = 8056

=> x = 8056 : 2014 = 4 

a) ( 2x - 15 )⁵ = ( 2x - 15 )³

( 2x - 15 )⁵ - ( 2x - 15 )³ = 0

\(\left(2x-15\right)^3.\left[\left(2x-15\right)^2-1\right]=0\)

\(\Rightarrow\orbr{\begin{cases}\left(2x-15\right)^3=0\\\left(2x-15\right)^2-1=0\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}2x-15=0\\\left(2x-15\right)^2=1\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}2x=15\\2x-15=1\text{ hoặc }2x-15=-1\end{cases}\Rightarrow\orbr{\begin{cases}x=\frac{15}{2}\\x=8\text{ hoặc }x=7\end{cases}}}\)

b, x + ( x + 1 ) + ( x + 2 ) + ... + ( x + 2013) = 2035147

( x + x + x + ... + x ) + ( 1 + 2 + ... + 2013 ) = 2035147

2014x + 2027091 = 2035147

2014x = 2035147 - 2027091

2014x = 8056

x = 8056 : 2014

x = 4 

\(a,\Leftrightarrow3\left(x+3\right)=0\Leftrightarrow x=-3\\ b,\Leftrightarrow\left(x^2-2\right)\left(6x+1\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x^2=2\\6x=-1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\sqrt{2}\\x=-\sqrt{2}\\x=-\dfrac{1}{6}\end{matrix}\right.\\ c,\Leftrightarrow\left(x-2013\right)\left(4x-1\right)=0\Leftrightarrow\left[{}\begin{matrix}x=2013\\x=\dfrac{1}{4}\end{matrix}\right.\\ d,\Leftrightarrow\left(x+1\right)^2-\left(x+1\right)=0\\ \Leftrightarrow\left(x+1\right)\left(x+1-1\right)=0\\ \Leftrightarrow x\left(x+1\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=0\\x=-1\end{matrix}\right.\)