Tìm x biết :
\(172x^2-7^9:98^3=2^{-3}\)
Tìm x biết:
172x2 - 79 : 983 = 2-3
172x2 - 79 : 983 = 2-3
<=> 172x2 - 79 : ( 2 . 72 )3 = 1/8
<=> 172x2 - 79 : ( 23 . 76 ) = 1/8
<=> 172x2 - 79 : 23 : 76 = 1/8
<=> 172x2 - 73 : 23 = 1/8
<=> 172x2 - ( 7 : 2 )3 = 1/8
<=> 172x2 - 343/8 = 1/8
<=> 172x2 = 43
<=> x2 = 43/172 = 1/4
<=> x = ±1/2
Tìm x biết :
\(172x^2-7^9:98^3=2^{-3}\)
\(\left(\frac{-3}{4}\right)^{3x-1}=\frac{256}{81}\)
\(a.172x^2-7^9=2^{-3}.98^3=117649\)
\(172x^2=117649+7^9=40471256\)
\(x^2=40471256:172=235298\)
\(x=\sqrt{235298}=485.07......\)
cái gì ? Mk đã học đến \(\sqrt{ }\) cái này đâu
tìm x biết:
a) \(5^x.\left(5^3\right)^2=625\)
b)\(\left(\dfrac{12}{15}\right)^x=\left(\dfrac{5}{3}\right)^{-5}-\left(-\dfrac{3}{5}\right)^4\)
c)\(\left(-\dfrac{3}{4}\right)^{3x-1}=\dfrac{256}{81}\)
d)\(172x^2-7^9:98^3=2^{-3}\)
Tim x
172x^2-7^9:98^3=a/23
\(172x^2-7^9:98^3=2^{-3}\)
=>172x^2-343/8=1/8
=>172x^2=344/8
=>x^2=2/8
=>x=1/2 hoặc x=-1/2
tìm x:
\(a,5^x.\left(5^2\right)^3=625\)
\(b,\left(\dfrac{12}{15}\right)^x=\left(\dfrac{5}{4}\right)^{-2}-\left(\dfrac{-3}{5}\right)^4\)
\(c,\left(\dfrac{-3}{4}\right)^{3x-1}=\dfrac{256}{81}\)
\(d,172x^2-7^9:98^3=2^{-3}\)
f.172x2-79:983=2-3
Giúp e vs. e cần gấp. thank you nha
(3x-2)^2=0
(x+3)^3=-27
5^x . (5^3)^2= 625
172x^2 = -7^9 : 98^3=2^-3
e.(-3/4)3x-1=256/81
f.172x2-79:983=2-3