a: 3x-2=2x-3

=>x=-1

b: 2x+3=5x+9

=>-3x=6

=>x=-2

c: 5-2x=7

=>2x=-2

=>x=-2

d: 10x+3-5x=4x+12

=>5x+3=4x+12

=>x=9

e: 11x+42-2x=100-9x-22

=>9x+42=78-9x

=>18x=36

=>x=2

f: 2x-(3-5x)=4(x+3)

=>2x-3+5x=4x+12

=>7x-3=4x+12

=>3x=15

=>x=5

a, \(231-\left(x-6\right)=1339:13\)

\(\Leftrightarrow231-\left(x-6\right)=103\)

\(\Leftrightarrow x-6=128\)

\(\Leftrightarrow x=134\)

Vậy .....

b, \(70-5\left(2x-3\right)=45\)

\(\Leftrightarrow5\left(2x-3\right)=25\)

\(\Leftrightarrow2x-3=5\)

\(\Leftrightarrow2x=8\)

\(\Leftrightarrow x=4\)

Vậy ....

c, \(156-\left(x+61\right)=82\)

\(\Leftrightarrow x+61=74\)

\(\Leftrightarrow x=13\)

Vậy ....

d, \(6\left(5x+35\right)=330\)

\(\Leftrightarrow5x+35=55\)

\(\Leftrightarrow5x=20\)

\(\Leftrightarrow x=4\)

Vậy ......

e, \(936-\left(4x+24\right)=72\)

\(\Leftrightarrow4x+24=864\)

\(\Leftrightarrow4x=840\)

\(\Leftrightarrow x=210\)

Vậy ...

231-(x-6)=1339:13

237-x=103

=>x=237-103=134

Vậy x=134

70-5(2x-3)=45

70-10x+15=45

=>-10x=45-15-70=-40

=>x=4

Vậy x=4

Các caau sau tương tự nhé bn

a, 231 - ( x - 6 ) = 1339 : 13

231 - ( x -6 ) = 103

x - 6 = 231 - 103 = 128

x = 128 + 6 = 134

b, 70 - 5 (2x -3 ) = 45

5 ( 2x -3 ) = 70 - 45 = 25

( 2x -3 ) = 25 : 5 = 5

2x = 5 + 3 = 8

x = 8 : 2 = 4

c, 156 - ( x + 61 ) = 82

x + 61 = 156 - 82 =74

x = 74 - 61

x = 13

d, 6 ( 5x + 35 ) = 330

5x + 35 = 330 : 6 = 55

5x = 55 - 35 = 20

x = 20 : 5 = 4

e, 936-(4x+ 24 ) = 72

4x + 24 = 936 - 72 = 864

4x = 864 - 24 = 840

x = 840 : 4 = 210

Chuc ban hoc tot nhe

Ta có : \(x^4+2x^3+5x^2+4x-12=0\)

\(\Leftrightarrow x^4+2x^3+5x^2+10x-6x-12=0\)

\(\Leftrightarrow x^3\left(x+2\right)+5x\left(x+2\right)-6\left(x+2\right)=0\)

\(\Leftrightarrow\left(x+2\right)\left(x^3+5x-6\right)=0\)

\(\Leftrightarrow\left(x+2\right)\left(x^3-x^2+x^2-x+6x-6\right)=0\)

\(\Leftrightarrow\left(x+2\right)\left[x^2\left(x-1\right)+x\left(x-1\right)+6\left(x-1\right)\right]=0\)

\(\Leftrightarrow\left(x+2\right)\left(x-1\right)\left(x^2+x+6\right)=0\)

\(\Leftrightarrow\)\(x+2=0\)

hoặc   \(x-1=0\)

hoặc   \(x^2+x+6=0\)

\(\Leftrightarrow\) \(x=-2\)(tm)

hoặc    \(x=1\)(tm)

hoặc   \(\left(x+\frac{1}{2}\right)^2+\frac{23}{4}=0\)(ktm)

Vậy tập nghiệm của phương trình là \(S=\left\{-2;1\right\}\)

A+B+C

=2x^3-5x^2+x-7+x^2-2x+6+C

=2x^3-4x^2-x-1-x^3+4x^2-1

=x^3-x-2

\(A=-x^2+4x+7=-\left(x^2-4x+4\right)+11=-\left(x-2\right)^2+11\)

Ta thấy : \(-\left(x-2\right)^2+11\le11\)\(\Leftrightarrow maxA=11\)khi    \(x=2\)

\(B=-4x^2+4x-5=-\left(4x^2-4x+1\right)-4=-\left(2x-1\right)^2-4\)

Ta thấy : \(-\left(2x-1\right)^2-4\le-4\)\(\Leftrightarrow maxB=-4\)khi   \(x=\frac{1}{2}\)

\(C=-x^2+x+5=-\left(x^2-2\cdot\frac{1}{2}\cdot x+\frac{1}{4}\right)+\frac{21}{4}=-\left(x-\frac{1}{2}\right)^2+\frac{21}{4}\)

Ta thấy : \(-\left(x-\frac{1}{2}\right)^2+\frac{21}{4}\le\frac{21}{4}\)\(\Leftrightarrow maxC=\frac{21}{4}\)khi    \(x=\frac{1}{2}\)

tk mk nka !!! 

thanks

a,  x - 3 : 2 = 5 14 : 5 12

=>  x - 3 : 2 = 5 2

=>  x - 3 : 2 = 25

=> x – 3 = 25

=> x = 53

b,  30 : x - 7 = 15 19 : 15 18

=>  30 : x - 7 = 15

=> x – 7 = 2

=> x = 9

c,  x 70 = x

=>  x 70 - x = 0

=>  x ( x 69 - 1 ) = 0

=> 

d,  2 x + 1 3 = 9 . 81

=>  2 x + 1 3 = 9 3

=> 2x + 1 = 9

=> x = 4

e,  5 x + 5 x + 2 = 650

=>  5 x 1 + 5 2 = 650

=>  5 x . 26 = 650

=>  5 x = 25

=> x = 2

f,  4 x - 1 2 = 25 . 9

=> 4 x - 1 2 = 5 2 . 3 2

=>  4 x - 1 2 = 15 2

=> 4x – 1 = 15

=> x = 4