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= (8.125). (25.4).3³

=  1000. 100.9
= 100 000.9
= 900 000

8.4.3^3.125.25

=(8.125).(25.4).27

=1000.100.27

=2100000

(10³ + 10⁴ + 125²) : 5³

= (2³.5³ + 2⁴.5⁴ + 5⁶) : 5³

= 5³.(2³ + 2⁴.5 + 5³) : 5³

= 2³ + 2⁴.5 + 5³

= 8 + 16.5 + 125

= 8 + 80 + 125

= 213

a)=-720

b)=616

c)=10000

d)=-60000

a) 12 . ( - 5 ) . ( - 2 ) . ( - 6 )

= - 60 . 12

= - 720

b) ( - 4 ) . 7 . 11 . ( - 2 )

= - 28 . ( - 22 )

= 616

c) 25 . ( - 5 ) . 4 ( - 20 )

= - 125 . ( - 80 )

= 10 000

d) 125 . ( - 3 ) . ( - 8 ) . ( - 10 )

= - 375 . 80

= - 30 000

\(a,\dfrac{5^{16}\cdot27^7}{125^5\cdot9^{11}}=\dfrac{5^{16}\cdot\left(3^3\right)^7}{\left(5^3\right)^5\cdot\left(3^2\right)^{11}}\)

\(=\dfrac{5^{16}\cdot3^{21}}{5^{15}\cdot3^{22}}=\dfrac{5}{3}\)

\(b,\left(-0,2\right)^2\cdot5-\dfrac{2^{13}\cdot27^3}{4^6\cdot9^5}\)

\(=0,04\cdot5-\dfrac{2^{13}\cdot\left(3^3\right)^3}{\left(2^2\right)^6\cdot\left(3^2\right)^5}\)

\(=0,2-\dfrac{2^{13}\cdot3^9}{2^{12}\cdot3^{10}}\)

\(=0,2-\dfrac{2}{3}\)

\(=-\dfrac{7}{15}\)

\(c,\dfrac{5^6+2^2\cdot25^3+2^3\cdot125^2}{26\cdot5^6}\)

\(=\dfrac{5^6+2^2\cdot\left(5^2\right)^3+2^3\cdot\left(5^3\right)^2}{5^6\cdot26}\)

\(=\dfrac{5^6+4\cdot5^6+8\cdot5^6}{5^6\cdot26}\)

\(=\dfrac{5^6\left(1+4+8\right)}{5^6\cdot26}\)

\(=\dfrac{13}{26}\)

\(=\dfrac{1}{2}\)

#\(Toru\)

\(a,\dfrac{5^{16}.27^7}{125^5.9^{11}}=\dfrac{\left(5^2\right)^8.9^7.3^7}{25^5.5^5.9^{11}}\\ =\dfrac{25^8.9^7.\left(3^2\right)^3.3}{25^5.\left(5^2\right)^2.5.9^{11}}=\dfrac{25^8.9^7.9^3.3}{25^5.25^2.5.9^{11}}\\ =\dfrac{25^8.9^{10}.3}{25^7.5.9^{11}}=\dfrac{25^7.9^{10}.25.3}{25^7.9^{10}.5.9}\\ =\dfrac{25.3}{5.9}=\dfrac{5.5.3}{5.3.3}=\dfrac{5}{3}\)