\(1-\dfrac{1212}{1616}\)

\(=1-\dfrac{3}{4}\)

\(=\dfrac{4}{4}-\dfrac{3}{4}\)

\(=\dfrac{1}{4}\)

404/1616

\(=\dfrac{11}{8}-\dfrac{3}{8}-\dfrac{3}{4}=1-\dfrac{3}{4}=\dfrac{1}{4}\)

=11/8−3/8−3/4=1−3/4=1/4

1/4

\(\frac{99}{72}-\frac{15}{40}-\frac{1212}{1616}\)= \(\frac{11}{8}-\frac{3}{8}-\frac{6}{8}\)

                                       =\(\frac{11-3-6}{8}\)

                                       =\(\frac{2}{8}=\frac{1}{4}\)

Ai thấy đúng thì k nha

Yêu các bạn nhiều

Đáp án là 1/4

+)\(\frac{99}{72}=\frac{11}{8}\)

+)\(\frac{15}{40}=\frac{3}{8}\)

+)\(\frac{1212}{1616}=\frac{12}{16}\)

\(\Rightarrow\frac{99}{72}-\frac{15}{40}-\frac{1212}{1616}=\frac{11}{8}-\frac{3}{8}-\frac{12}{16}=\frac{1}{4}\)

\(\frac{2323+1313+1414+1515+1616}{4141+2222+2323+2424+2525}\)

=\(\frac{8181}{13635}\)

18180,8               

\(\dfrac{1111}{1212}\)  và  \(\dfrac{1515}{1616}\)

\(\dfrac{1111}{1212}=\dfrac{1111\times1616}{1212\times1616}=\dfrac{1795376}{1958592}\)

\(\dfrac{1515}{1616}=\dfrac{1515\times1212}{1616\times1212}=\dfrac{1836180}{1958592}\)

Vì: 1836180 > 1795376

=> \(\dfrac{1111}{1212}< \dfrac{1515}{1616}\)

\(\dfrac{1111}{1212}\) = \(\dfrac{1111:101}{1212:101}\) = \(\dfrac{11}{12}\)= 1 - \(\dfrac{1}{12}\) ;    \(\dfrac{1515}{1616}\) =\(\dfrac{1515:101}{1616:101}\) = \(\dfrac{15}{16}\) = 1 -\(\dfrac{1}{16}\)

Vì \(\dfrac{1}{12}\) > \(\dfrac{1}{16}\) nên  \(\dfrac{1111}{1212}\) < \(\dfrac{1515}{1616}\)

\(\dfrac{1111}{1212}=\dfrac{11}{12}=1-\dfrac{1}{12}\)

\(\dfrac{1516}{1516}=\dfrac{15}{16}=1-\dfrac{1}{16}\)

Vì: \(\dfrac{1}{12}>\dfrac{1}{16}\) nên \(1-\dfrac{1}{12}< 1-\dfrac{1}{16}\)

Vậy\(\dfrac{1111}{1212}< \dfrac{1515}{1616}\)

mình trả lời bạn k mình nhé

ok bạn