\(\frac{9x8x5}{6x4x15}\)
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tính 9x8x5 phần 6x4x15
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Tính
\(\frac{9x8x5}{6x4x15}\)
9 * 8 * 5 = 360
6 * 4 * 15 = 600
360 /600 = 3/5
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9 x 8 x 5 / 6 x 4 x 15 = 9 x 4 x 2 x 5 / 6 x 4 x 3x 5 = 9 x 2 / 6 x 3 = 3 x 3 /2 x 3=3/2
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\(\frac{9x8x5}{6x4x15}=\frac{3x3x2x4x5}{2x3x4x3x5}=1\)
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Tính nhanh :
9x8x5
6x4x15
Bằng 1 nhé
Các bạn ủng hộ cho tớ đê !!!!!!!!!!!!!!!!!!!!1
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9 x 8 x 5 = 9 x 5 x 8
= 40 x 8
= 320
6 x 4 x 15 = 4 x 15 x 6
= 60 x 6
= 360
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9x8x5
6x4x15
= \(\frac{3x3x4x4x5}{3x2x4x5x3}=\frac{4x5}{2}=\frac{20}{2}=10\)
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\(\frac{9x8x5}{6x4x15}\)
\(\frac{3x3x2x4x5}{3x2x4x5x3}\)
1
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\(\frac{9\cdot8\cdot5}{6\cdot4\cdot15}\)
\(=\frac{3\cdot2\cdot1}{2\cdot1\cdot3}\)
\(=1\)
nếu thấy đúng thì k cho tớ nha
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tính:
a).2x3x4x5
3x4x5x6
b).9x8x5
6x4x15
ai nhanh tick
a, \(\frac{2x3x4x5}{3x4x5x6}\)= \(\frac{2}{6}\)=\(\frac{1}{3}\)
b, \(\frac{9x8x5}{6x4x15}\)=\(\frac{3x3x4x2x5}{2x3x4x3x5}\)=1
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a, 1 x 1x1x1 / 1x1x1x3
= 1 / 3
b, 9x2x1 / 6x1x3
= 18 / 18
= 1
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9x8x5= 6x4x15
9x8x5=ra phan so 6x4x15
\(9.8.5=\frac{360}{1}\) \(6.4.15=\frac{360}{1}\)
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1
tick minh nha ai tick minh người ấy có tiền cả năm
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khong phai dau ra phan so co ma
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$frac{45}{53}.left(frac{17}{3}-frac{53}{47}right)+frac{17}{3}.left(frac{6}{17}-frac{47}{53}right)$$frac{45}{53}.left(frac{17}{3}-frac{53}{47}right)+frac{17}{3}.left(frac{6}{17}-frac{47}{53}right)$$frac{45}{53}.left(frac{17}{3}-frac{53}{47}right)+frac{17}{3}.left(frac{6}{17}-frac{47}{53}right)$$frac{45}{53}.left(frac{17}{3}-frac{53}{47}right)+frac{17}{3}.left(frac{6}{17}-frac{47}{53}right)$$frac{45}{53}.left(frac{17}{3}-frac{53}{47}right)+frac{17}{3}.left(frac{6}{17}-frac{47}{53}right)$$frac{45}{...
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{53}\right)$$\frac{45}{53}.\left(\frac{17}{3}-\frac{53}{47}\right)+\frac{17}{3}.\left(\frac{6}{17}-\frac{47}{53}\right)$$\frac{45}{53}.\left(\frac{17}{3}-\frac{53}{47}\right)+\frac{17}{3}.\left(\frac{6}{17}-\frac{47}{53}\right)$$\frac{45}{53}.\left(\frac{17}{3}-\frac{53}{47}\right)+\frac{17}{3}.\left(\frac{6}{17}-\frac{47}{53}\right)$$\frac{45}{53}.\left(\frac{17}{3}-\frac{53}{47}\right)+\frac{17}{3}.\left(\frac{6}{17}-\frac{47}{53}\right)$$\frac{45}{53}.\left(\frac{17}{3}-\frac{53}{47}\right)+\frac{17}{3}.\left(\frac{6}{17}-\frac{47}{53}\right)$$\frac{45}{53}.\left(\frac{17}{3}-\frac{53}{47}\right)+\frac{17}{3}.\left(\frac{6}{17}-\frac{47}{53}\right)$$\frac{45}{53}.\left(\frac{17}{3}-\frac{53}{47}\right)+\frac{17}{3}.\left(\frac{6}{17}-\frac{47}{53}\right)$$\frac{45}{53}.\left(\frac{17}{3}-\frac{53}{47}\right)+\frac{17}{3}.\left(\frac{6}{17}-\frac{47}{53}\right)$$\frac{45}{53}.\left(\frac{17}{3}-\frac{53}{47}\right)+\frac{17}{3}.\left(\frac{6}{17}-\frac{47}{53}\right)$$\frac{45}{53}.\left(\frac{17}{3}-\frac{53}{47}\right)+\frac{17}{3}.\left(\frac{6}{17}-\frac{47}{53}\right)$$\frac{45}{53}.\left(\frac{17}{3}-\frac{53}{47}\right)+\frac{17}{3}.\left(\frac{6}{17}-\frac{47}{53}\right)$$\frac{45}{53}.\left(\frac{17}{3}-\frac{53}{47}\right)+\frac{17}{3}.\left(\frac{6}{17}-\frac{47}{53}\right)$$\frac{45}{53}.\left(\frac{17}{3}-\frac{53}{47}\right)+\frac{17}{3}.\left(\frac{6}{17}-\frac{47}{53}\right)$$\frac{45}{53}.\left(\frac{17}{3}-\frac{53}{47}\right)+\frac{17}{3}.\left(\frac{6}{17}-\frac{47}{53}\right)$$\frac{45}{53}.\left(\frac{17}{3}-\frac{53}{47}\right)+\frac{17}{3}.\left(\frac{6}{17}-\frac{47}{53}\right)$$\frac{45}{53}.\left(\frac{17}{3}-\frac{53}{47}\right)+\frac{17}{3}.\left(\frac{6}{17}-\frac{47}{53}\right)$$\frac{45}{53}.\left(\frac{17}{3}-\frac{53}{47}\right)+\frac{17}{3}.\left(\frac{6}{17}-\frac{47}{53}\right)$$\frac{45}{53}.\left(\frac{17}{3}-\frac{53}{47}\right)+\frac{17}{3}.\left(\frac{6}{17}-\frac{47}{53}\right)$$\frac{45}{53}.\left(\frac{17}{3}-\frac{53}{47}\right)+\frac{17}{3}.\left(\frac{6}{17}-\frac{47}{53}\right)$$\frac{45}{53}.\left(\frac{17}{3}-\frac{53}{47}\right)+\frac{17}{3}.\left(\frac{6}{17}-\frac{47}{53}\right)$$\frac{45}{53}.\left(\frac{17}{3}-\frac{53}{47}\right)+\frac{17}{3}.\left(\frac{6}{17}-\frac{47}{53}\right)$$\frac{45}{53}.\left(\frac{17}{3}-\frac{53}{47}\right)+\frac{17}{3}.\left(\frac{6}{17}-\frac{47}{53}\right)$$\frac{45}{53}.\left(\frac{17}{3}-\frac{53}{47}\right)+\frac{17}{3}.\left(\frac{6}{17}-\frac{47}{53}\right)$$\frac{45}{53}.\left(\frac{17}{3}-\frac{53}{47}\right)+\frac{17}{3}.\left(\frac{6}{17}-\frac{47}{53}\right)$$\frac{45}{53}.\left(\frac{17}{3}-\frac{53}{47}\right)+\frac{17}{3}.\left(\frac{6}{17}-\frac{47}{53}\right)$$\frac{45}{53}.\left(\frac{17}{3}-\frac{53}{47}\right)+\frac{17}{3}.\left(\frac{6}{17}-\frac{47}{53}\right)$$\frac{45}{53}.\left(\frac{17}{3}-\frac{53}{47}\right)+\frac{17}{3}.\left(\frac{6}{17}-\frac{47}{53}\right)$$\frac{45}{53}.\left(\frac{17}{3}-\frac{53}{47}\right)+\frac{17}{3}.\left(\frac{6}{17}-\frac{47}{53}\right)$$\frac{45}{53}.\left(\frac{17}{3}-\frac{53}{47}\right)+\frac{17}{3}.\left(\frac{6}{17}-\frac{47}{53}\right)$$\frac{45}{53}.\left(\frac{17}{3}-\frac{53}{47}\right)+\frac{17}{3}.\left(\frac{6}{17}-\frac{47}{53}\right)$$\frac{45}{53}.\left(\frac{17}{3}-\frac{53}{47}\right)+\frac{17}{3}.\left(\frac{6}{17}-\frac{47}{53}\right)$$\frac{45}{53}.\left(\frac{17}{3}-\frac{53}{47}\right)+\frac{17}{3}.\left(\frac{6}{17}-\frac{47}{53}\right)$$\frac{45}{53}.\left(\frac{17}{3}-\frac{53}{47}\right)+\frac{17}{3}.\left(\frac{6}{17}-\frac{47}{53}\right)$$\frac{45}{53}.\left(\frac{17}{3}-\frac{53}{47}\right)+\frac{17}{3}.\left(\frac{6}{17}-\frac{47}{53}\right)$$\frac{45}{53}.\left(\frac{17}{3}-\frac{53}{47}\right)+\frac{17}{3}.\left(\frac{6}{17}-\frac{47}{53}\right)$$\frac{45}{53}.\left(\frac{17}{3}-\frac{53}{47}\right)+\frac{17}{3}.\left(\frac{6}{17}-\frac{47}{53}\right)$$\frac{45}{53}.\left(\frac{17}{3}-\frac{53}{47}\right)+\frac{17}{3}.\left(\frac{6}{17}-\frac{47}{53}\right)$$\frac{45}{53}.\left(\frac{17}{3}-\frac{53}{47}\right)+\frac{17}{3}.\left(\frac{6}{17}-\frac{47}{53}\right)$$\frac{45}{53}.\left(\frac{17}{3}-\frac{53}{47}\right)+\frac{17}{3}.\left(\frac{6}{17}-\frac{47}{53}\right)$$\frac{45}{53}.\left(\frac{17}{3}-\frac{53}{47}\right)+\frac{17}{3}.\left(\frac{6}{17}-\frac{47}{53}\right)$$\frac{45}{53}.\left(\frac{17}{3}-\frac{53}{47}\right)+\frac{17}{3}.\left(\frac{6}{17}-\frac{47}{53}\right)$v
I. Nội qui tham gia "Giúp tôi giải toán"
1. Không đưa câu hỏi linh tinh lên diễn đàn, chỉ đưa các bài mà mình không giải được hoặc các câu hỏi hay lên diễn đàn;
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\(y=\frac{1}{x^2+\sqrt{x}}\int^{ }_{ }^{ }^2_{ }_{ }\vec{\vec{\vec{^2\frac{\frac{\frac{\sqrt[]{}\sqrt[]{}\sqrt[]{}\sqrt[]{}\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{\frac{ }{ }}{ }}{ }}{ }}{ }}{ }}{ }}{ }}{ }}{ }}{ }}{ }}{ }}{ }}{ }}{ }}{ }}{ }}{ }}}}\)